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djverab [1.8K]
3 years ago
8

The radar system of a navy cruiser transmits at a wavelength of 1.4 cm, from a circular antenna with a diameter of 2.7 m. At a r

ange of 7.8 km, what is the smallest distance in meters that two speedboats can be from each other and still be resolved as two separate objects by the radar system?
Physics
1 answer:
Goshia [24]3 years ago
4 0

Answer:

Distance will be 49.34 m

Explanation:

We have given wavelength \lambda =1.4cm =0.014m

Diameter of the antenna d = 2.7 m

Range L = 7.8 km = 7800 m

We have to find the smallest distance hat two speedboats can be from each other and still be resolved as two separate objects D

We know that distance is given by D=\frac{L1.22\lambda }{d}=\frac{7800\times 1.22\times 0.014}{2.7}=49.3422m

So distance D will be 49.34 m

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The water cycle basically involves five steps:

  • evaporation and transpiration ⇄
  • condensation, ⇄
  • precipitation, ⇄
  • runoff, ⇄
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So when a <u>thunderstorm </u>occurs it <em>helps in completing the precipitation process </em>by enabling the release of water vapor stored up in the atmosphere to fall on the ground as rain.

After this, the water <em>runoffs </em><em>to the surface of the ground, on plants, into rocks, rivers, and lakes.</em>

Next, the <em>Infiltration process</em> enables the water on the ground surface to enter the soil some of which becomes groundwater.

The cycle begins again as the<em> </em><em>evaporation and transpiration</em> <em>process </em>begins, where the groundwater as a result of heat from the sun is taken back into the atmosphere, while water in plants by means of transpiration goes back <em>into the atmosphere</em>.

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3 years ago
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Martin needs to push a box up a ramp.
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A 10 kg object dropped from a certain window strikes the ground in 4.0 s. neglecting air resistance, a 5 kg object dropped from
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v = a/√(2h/g) m/s

Explanation:

Lets say the distance away from the cliff is a.

then, a = v t

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