Answer:
a) C_v = 1.005 KJ/kgK
b) C_v = 1005.000 J/kgC
c) C_v = 0.240 kcal/kgC
d) C_v = 0.240 Btu/lbmF
Explanation:
Given:
- constant-pressure specific heat C_v = 1.005 KJ/kgC
Find C_v in units of:
a) kJ/kg·K
b) J/g·°C
c) kcal/ kg·°C
d) Btu/lbm·°F
Solution:
a) C_v is Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass. Usually, it's the heat in Joules needed to raise the temperature of 1 gram of sample 1 Kelvin or 1 degree Celsius. Hence,
C_v = 1.005 KJ/kgK
b)
C_v = 1.005 KJ/kgC * ( 1000 J / KJ)
C_v = 1005.000 J/kgC
c)
C_v = 1.005 KJ/kgC * ( 0.239006 kcal / KJ)
C_v = 0.240 kcal/kgC
d)
C_v = 1.005 KJ/kgC * ( 0.947817 Btu / KJ) * ( kg / 2.205 lbm)*(Δ1 C / Δ1.8 F)
C_v = 0.240 Btu/lbmF
Magnitudes of the currents are i1= 0.00104A , i2= 0.003641A , i3= 0.00508A.
Explanation:
Using superposition theorem,
remove the E1 voltage supply source and calculate resistance across it.
From the circuit given, as the resistances R1 and R2 are parallel
using the formula R1//R2=(R1.R2/(R1+R3)
V1= ((r1||r2)/(r1+r2||r3))*E1
v1 = (((1kΩ*680Ω)/(1kΩ+680Ω))/(3.3kΩ +((1kΩ*680Ω)/(1kΩ+680Ω)))*10v
v1= 2.3v
v2 = ((r1||r2)/(r1+r2||r3))*E2
v2 = (((1kΩ*680Ω)/(1kΩ+680Ω))/(3.3kΩ +((1kΩ*680Ω)/(1kΩ+680Ω)))*5v
v2= 1.161v
V = V1+V2
=> 2.3 + 1.161
=> 3.461v
Magnitudes of the currents can be found by i=v/r
i1 = v/r1
=> 3.461/3.3kΩ
=>0.00104A
i2=2.89/1kΩ
=>0.003461A
i3=2.89/680Ω
=> 0.00508A.
Therefore the magnitudes of the currents are i1, i2, and i3.
Answer:c
Explanation:
Because it will take out the fuel right away
Answer:
Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy.