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3 years ago

What is the overall electric charge for individual atoms on the periodic table of elements?

Chemistry

2 answers:

Vaselesa [24]3 years ago

6 0

Explanation:

All the atoms present in periodic table are neutral in nature and it is known that a neutral atom means that it contains no charge.

For example, sodium is present as Na in the periodic table. And, it does not contain any charge.

When a neutral atom loses or gains an electron then it acquires a charge.

For example, atomic number of calcium is 20 and its electronic distribution is 2, 8, 8, 2. Hence, in order to acquire stability when it loses 2 valence electrons then neutral atom of Ca changes into $Ca^{2+}$ .

Hence, it means that by loosing 2 valence electrons calcium has an electric charge of +2.

miv72 [106K]3 years ago

4 0

Answer:

Neutral

Explanation:

Atoms on the periodic table all have neutral electric charges. This is because they have an equal number of protons, which are positivly charged, and electrons, which are negatively charged.

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What are atoms in a simple form

IgorC [24]

Answer:

atom is the smallest unit of ordinary matter that forms a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small, typically around 100 picometers across.

7 0

3 years ago

Read 2 more answers

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

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3 years ago

If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it

Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

$NO_2\rightarrow NO+\frac{1}{2}O_2$

The reaction is second order for $NO_2$ with a rate constant of $0.543M^{-1}s^{-1}$ at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M