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seraphim [82]
3 years ago
8

People learn best in different ways. By combining all the group presentations, your class will explain how they see the optical

illusion in a way that every student will be able to understand. Which presentation helped you understand how you saw the optical illusion best?
Engineering
2 answers:
nexus9112 [7]3 years ago
6 0
This sounds like a multiple choice question so without the choices or the “group presentations” we can’t solve this
DENIUS [597]3 years ago
4 0

Answer:

People learn best in different ways. By combining all the group presentations, your class will explain how they see the optical illusion in a way that every student will be able to understand. Which presentation helped you understand how you saw the optical illusion best?

I cont under stand

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Solid Isomorphous alloys strength
Sphinxa [80]

Answer:

Explanation:

ℎ

3 0
3 years ago
The 15-kg block A slides on the surface for which µk = 0.3. The block has a velocity v = 10 m/s when it is s = 4 m from the 10-k
sammy [17]

Answer:

s_max = 0.8394m

Explanation:

From equilibrium of block, N = W = mg

Frictional force = μ_k•N = μ_k•mg

Since μ_k = 0.3,then F = 0.3mg

To determine the velocity of Block A just before collision, let's apply the principle of work and energy;

T1 + ΣU_1-2 = T2

So, (1/2)m_a•(v_ao)² - F•s =(1/2)m_a•(v_a1)²

Plugging in the relevant values to get ;

(1/2)•(15)•(10)² - (0.3•15•9.81•4) =(1/2)(15)•(v_a1)²

750 - 176.58 = 7.5(v_a1)²

v_a1 = 8.744 m/s

Using law of conservation of momentum;

Σ(m1v1) = Σ(m2v2)

Thus,

m_a•v_a1 + m_b•v_b1 = m_a•v_a2 + m_b•v_b2

Thus;

15(8.744) + 10(0) = 15(v_a2) + 10(v_b2)

Divide through by 5;

3(8.744) + 2(0) = 3(v_a2) + 2(v_b2)

Thus,

3(v_a2) + 2(v_b2) = 26.232 - - - (eq1)

Coefficient of restitution has a formula;

e = (v_b2 - v_a2)/(v_a1 - v_b1)

From the question, e = 0.6.

Thus;

0.6 = (v_b2 - v_a2)/(8.744 - 0)

0.6 x 8.744 = (v_b2 - v_a2)

(v_b2 - v_a2) = 5.246 - - - (eq2)

Solving eq(1) and 2 simultaneously, we have;

v_b2 = 8.394 m/s

v_a2 = 3.148 m/s

Now, to find maximum compression, let's apply conservation of energy on block B;

T1 + V1 = T2 + V2

Thus,

(1/2)m_b•(v_b2)² + (1/2)k(s_1)² = (1/2)m_b•(v_b'2)² + (1/2)k(s_max)²

(1/2)10•(8.394)² + (1/2)1000(0)² = (1/2)10•(0)² + (1/2)(1000)(s_max)²

500(s_max)² = 352.29618

(s_max)² = 352.29618/500

(s_max)² = 0.7046

s_max = 0.8394m

8 0
3 years ago
The production process of rods from machine "A" yields specimen with the following specs. Mean: µ(LA)=20.00mm, STD: s(LA)=0.50mm
Oxana [17]

Answer: the standard deviation STD of machine B is s (Lb) = 0.4557

Explanation:

from the given data, machine A and machine B produce half of the rods

Lt = 0.5La + 0.5Lb

so

s² (Lt) = 0.5²s²(La) + 0.5²s²(Lb) + 0.5²(2)Cov (La, Lb)

but Cov (La, Lb) = Corr(La, Lb) s(La) s(Lb) = 0.4s (La) s(Lb)

so we substitute

s²(Lt) = 0.25s² (La) + 0.25s² (Lb) + 0.4s (La) s(Lb)

0.4² = 0.25 (0.5²) + 0.25s² (Lb) + (0.5)0.4(0.5) s(Lb)

0.64 = 0.25 + s²(Lb) + 0.4s(Lb)

s²(Lb) + 0.4s(Lb) - 0.39 = 0

s(Lb) = { -0.4 ± √(0.16 + (4*0.39)) } / 2

s (Lb) = 0.4557

therefore the standard deviation STD of machine B is s (Lb) = 0.4557

8 0
3 years ago
After reading through the code, what will happen when you click run?* 1 point when run move forward while there is a pile do rem
KATRIN_1 [288]

Explanation:

I'm not exactly a master at coding, but I'm pretty sure that:

The farmer will remove dirt as long as there is a pile, then stop when the pile is done.

5 0
2 years ago
HELP PLEASE ! TYYYY!!!!!!!!!!!!!!!!!!!!!!!!
My name is Ann [436]

You can pick the song Cover me in sunshine- By pink

  • <em>This</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>very</em><em> </em><em>beautiful</em><em> </em><em>song</em><em> </em><em>that</em><em> </em><em>describes</em><em> </em><em>happiness</em><em>.</em>
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  • <em>Also</em><em>,</em><em> </em><em>The</em><em> </em><em>song</em><em> </em><em>compares</em><em> </em><em>Sunshine</em><em> </em><em>with</em><em> </em><em>Happiness</em><em>.</em>
8 0
3 years ago
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