Which of the following does a finding of no significant impact (FONSI) negate the need for?

What does this work for

Anastaziya [24]

Answer:

it allows your dash board to light up you MPH RPM and all the other numbers on the spadomter

Explanat

8 0

3 years ago

Your local hospital is considering the following solution options to address the issues of congestion and equipment failures at

kiruha [24]

Jsjhjrhwjdbwjwjrueiworuuwud

4 0

2 years ago

On the pavement indicate that the adjacent lane is traveling in the same direction and passing is permitted

Mkey [24]

A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

A broken white line on the pavement show that the adjacent lane is traveling in the same direction and passing is permitted.

<h3>What does pavement markings show?</h3>

Pavement markings are known to be tools that are used to pass infor or messages to roadway users.

Note that they tell the part of the road that one need to use, give information about conditions ahead, and others

Note that A broken yellow line on the pavement tells that the adjacent lane is traveling in the opposite direction and passing is permitted.

Learn more about pavement markings from

brainly.com/question/10179521

#SPJ1

6 0

2 years ago

A reciprocating compressor takes a compresses it to 5 bar. Assuming that the compression is reversible and has an index, k, of 1

Gelneren [198K]

Answer:

final temperature is 424.8 K

so correct option is e 424.8 K

Explanation:

given data

pressure p1 = 1 bar

pressure p2 = 5 bar

index k = 1.3

temperature t1 = 20°C = 293 k

to find out

final temperature t2

solution

we have given compression is reversible and has an index k

so we can say temperature is

$\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }$ ...........1

put here all these value and we get t2

$\frac{t2}{293}= [\frac{5}{1}]^{\frac{1.3-1}{1.3} }$

t2 = 424.8

final temperature is 424.8 K

so correct option is e

5 0

3 years ago

1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer ra

Ann [662]

Answer:

$Hr=4.2*10^7\ btu/hr$

Explanation:

From the question we are told that:

Water flow Rate $R=4.5slug/s=144.78ib/sec$

Initial Temperature $T_1=60 \textdegree F$

Final Temperature $T_2=140 \textdegree F$

Let

Specific heat of water $\gamma= 1$

And

$\triangle T= 140-60$

$\triangle T= 80\ Deg.F$

Generally the equation for Heat transfer rate of water $H_r$ is mathematically given by

Heat transfer rate to water= mass flow rate* specific heat* change in temperature

$H_r=R* \gamma*\triangle T$

$H_r=144.78*80*1$

$H_r=11582.4\ btu/sec$

Therefore

$H_r=11582.4\ btu/sec*3600$

$Hr=4.2*10^7\ btu/hr$

3 0

3 years ago