Answer:
Ammonia, NH₃ >
ammonium nitrate, NH₄NO₃ > ammonium hydrogen phosphate, (NH₄)₂HPO₄
Explanation:
Mass percentage -
Mass percentage of A is given as , the mass of the substance A by mass of the total solution multiplied by 100.
i.e.
mass % A = mass of A / mass of solution * 100
Given,
mass of nitrogen = 14 g/mol
mass of hydrogen = 1 g/mol
mass of oxygen = 16 g/mol
mass of phosphorus = 31 g/mol
1. Ammonia, NH₃
Hence , the mass of solution is calculated as the summation of the mass of the atom * number of atom ,
Hence ,
mass of solution = 1 * 14 g/mol + 3 * 1 g/mol
mass of solution = 17 g/mol
and ,
mass of nitrogen = 14 g/mol
The mass percent of nitrogen can be calculated from using the above formula
mass % N = mass of N / mass of solution * 100
mass % N = 14 g/mol / 17 g/mol * 100
mass % N = 82.35 % .
2.
ammonium nitrate, NH₄NO₃
Hence , the mass of solution is calculated as the summation of the mass of the atom * number of atom ,
Hence ,
mass of solution = 2 * 14 g/mol + 4 * 1 g/mol + 3 * 16 g/mol
mass of solution = 80 g/mol
and ,
mass of nitrogen = 14 g/mol
The mass percent of nitrogen can be calculated from using the above formula
mass % N = mass of N / mass of solution * 100
mass % N = 14 g/mol / 80 g/mol * 100
mass % N = 17.50 % .
3. ammonium hydrogen phosphate, (NH₄)₂HPO₄
Hence , the mass of solution is calculated as the summation of the mass of the atom * number of atom ,
Hence ,
mass of solution = 2 * 14 g/mol + 9 * 1 g/mol + 4 * 16 g/mol + 1 * 31 g/mol
mass of solution = 132 g/mol
and ,
mass of nitrogen = 14 g/mol
The mass percent of nitrogen can be calculated from using the above formula
mass % N = mass of N / mass of solution * 100
mass % N = 14 g/mol / 132 g/mol * 100
mass % N = 10.60 % .
Hence , the correct order is -
Ammonia, NH₃ >
ammonium nitrate, NH₄NO₃ > ammonium hydrogen phosphate, (NH₄)₂HPO₄
= 0.15mol
atoms
atoms