Which type of perspective makes objects look similar to how they look in real life (select the best answer)

Describe the relationship between the mass volume and density of material

Answer: For a given mass and volume, how much physical space a material takes up, of an object or substance, the density remains constant at a given temperature and pressure. The equation for this relationship is ρ = m / V in which ρ (rho) is density, m is mass and V is volume, making the density unit kg/m3.

Explanation: Hope that helps

7 0

3 years ago

Read 2 more answers

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

<u>Explanation:</u>

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

According to the bohr model, what determines the shortest wavelength in a given series of wavelengths emitted by the atom?

algol13

According to the bohr model "The lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

By explaining that electrons move in fixed orbitals (shells) and not anywhere in between, Bohr theory amended the atomic structure model.

He also showed that each orbit (shell) has a fixed energy. Bohr refined Rutherford's model of the atom's nucleus to include electrons and their varying energy levels.

According to Rydberg formula

1/λ = R [1/ni² - 1/nf²]

λ = wavelength

R = Rydberg constant

ni & nf are integers or principal quantum numbers where nf > ni

So if we want wavelength(λ) to be shortest, then 1/nf should be zero.

In this way , it depends on nf and not on ni

That's why the lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

Learn more about Bohr's model here brainly.com/question/18002213

#SPJ4

4 0

2 years ago

How many grams of oxygen is needed to completelt react with of 9.30 of aluminum

Leona [35]

Hey there!

Given the reaction:

4 AI + 3O2 ------> 2 AI2O3

4 moles Al --------- 3 moles O2

9.30 moles Al --------- ?? moles O2

9.30 * 3 / 4 => 6.975 moles of O2

Molar mass O2 => 32.0 g

Therefore:

6.975 * 32.0 => 223.3 g of Oxygen

Hope that helps!

5 0

3 years ago

Calculate the molarity of 90.0 mL of a solution that is 0.92 % by mass NaCl. Assume the density of the solution is the same as p

jeka94

Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
m(solution) = 90 mL · 1 g/mL = 90 g.
m(NaCl) = 90 g · 0,0092 = 0,828 g.
n(NaCl) = 0,828 g ÷ 58,4 g/mol.
n(NaCl) = 0,014 mol.
c(solution) = 0,014 mol ÷ 0,09 L.
c(solution) = 0,155 mol/L.

8 0

3 years ago