Answer:
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Solution,
Hope this helps...
Good luck on your assignment...
The actual speed of the plane with the wind:
v² = ( 150 + 50 · cos 45°)² + ( 50 · sin 45°)²
v² = ( 150 + 35.355 )² + 35.355²
v² = 34,356.467 + 1,249.976
v = √35,606.452
v = 188.7 mph
-1/5of 15 =-3 then add 3 2/5th which is 17/2 so -3+17/2 = 11/2=5 1/2
Answer:
Area of equilateral triangle = 81√3 cm²
Step-by-step explanation:
Given:
Perimeter of an equilateral triangle = 54 cm
Find:
Area of equilateral triangle
Computation:
Perimeter of an equilateral triangle = 3 x Side
54 = 3 x Side
Side of equilateral triangle = 54 / 3
Side of equilateral triangle = 18 cm
Area of equilateral triangle = [√3/4]side²
Area of equilateral triangle = [√3/4][18]²
Area of equilateral triangle = [√3/4][324]
Area of equilateral triangle = [√3][81]
Area of equilateral triangle = 81√3 cm²
