Mass of sodium :- 23 grams
Mass of Chlorine :- 35.5 grams
Mass of NaCl :- 58.5 grams
mass given :- 25 grams
moles :- 0.432 ( given mass/ ionic mass)

Answer:
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Explanation:
Water potential = Pressure potential + solute potential


We have :
C = 0.15 M, T = 273.15 K
i = 1
The water potential of a solution of 0.15 m sucrose= 
(At standard temperature)


The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Answer:
height(h)=10 m
acceleration due to gravity (g)=10 m/s^2
mass (m)=?
potential energy=67
or,mgh= 67
or,m×10×10=67
or,m=67/100
or,m=0.67 kg
Therefore,m= 670 grams