3 years ago

Name two useful materials obtained from fractional distillation of petroleum

Chemistry

1 answer:

d1i1m1o1n [39]3 years ago

7 0

Answer: Petroleum or Natural gas and Kerosine

Explanation:

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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati

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Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

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$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time passed by the sample = 48.0 hr

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a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

$k=\frac{2.303}{48.0}\log\frac{53500}{42520}$

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Now we have to calculate the half-life.

$k=\frac{0.693}{t_{1/2}}$

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Therefore, the half life of 28-Mg in hours is, 6.94

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