Answer:
at 181.0
is -723.3 kJ/mol.
Explanation:
We know, 
where, T is temperature in kelvin.
Let's assume
and
does not change in the temperature range 25.0
- 181.0
.
= (273+181.0) K = 454.0 K
Hence, at 181.0
, ![\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-795.8kJ%2Fmol%29-%5B%28454.0%20K%29%5Ctimes%20%28-159.8%5Ctimes%2010%5E%7B-3%7DkJ%2FK.mol%29%5D)
= -723.3 kJ/mol
Dipole-dipole interactions, and London dispersion interactions
Answer:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Explanation:
The silver nitrate, AgNO₃, dissolves in water as follows:
AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)
The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:
<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
The element is Sr (strontium)
strontium is in atomic number 38 in the periodic table. Strontium has 2.8.8.8.8.2
it loses two electrons to become stable hence it has a charge of 2+. when strontium loses two electron it form ion with 36 electrons