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3 years ago

By adding "-once", one can form the noun form of the word "organize" is that true or false?

Engineering

2 answers:

garri49 [273]3 years ago

8 0

Answer:

False, mark brainlist?

Explanation:

denpristay [2]3 years ago

7 0

Answer:

<h2>False </h2>

Explanation:

The noun form of organize is just adding letter r

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A piston-cylinder device contains 0.15 kg of air initially at 2 MPa and 350 °C. The air is first expanded isothermally to 500 kP

Semmy [17]

Answer:

Isothermal expansion W₁ =-37198.9 J

Polytropic Compression W₂ =-34872.82 J

Isobaric Compression W₃ = -6974.566 J

The net work for the cycle = -79046.29 J

Explanation:

Mass of air = 0.15 kg = 150 g

Molar mass = 28.9647 g/mol

Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air

PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³

For isothermal expansion we have

P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³

Therefore work done

W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J

Stage 2

Compression polytropically we have

$\frac{P_2}{P_3} = (\frac{V_3}{V_2} )^n$ where P₃ = 2 MPa

Therefore V₃ = $(\frac{1}{4} )^{\frac{1}{1.2} }*V_2$ = 1.6904×10⁻² m³

Work = W₂ = $\frac{P_2V_2-P_3V_3}{n-1}$ = -34872.82 J

$\frac{P_2}{P_3} = (\frac{T_2}{T_3} )^\frac{n}{n-1}$ or T₃ = $T_2*(\frac{P_3}{P_2})^\frac{n-1}{n}$ = 785.12 K

Isobaric compression we have thus

Work done W₃ = P(V₁ -V₃) = -6974.566 J

Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J

7 0

3 years ago

A refrigerator removes heat from a refrigerated space at 0°C at a rate of 2.2 kJ/s and rejects it to an environment at 20°C. wha

Anika [276]

Answer:

The minimum power required by the refrigerator is 161 W to remove heat from a refrigerated space.

<u>Explanation:</u>

To calculate the power required to refrigerate we know that COP of refrigerator is represented as $C O P=\frac{Q_{\text {coid}}}{W}C O P=\frac{T_{\text {cold }}}{T_{\text {hot }}-T_{\text {cold}}}$ . Given that, $T_{\text {cold}}=0^{\circ} \mathrm{C}, T_{\text {hot}}=22^{\circ} \mathrm{C} \text { and } Q_{\text {cold}}=2.2 \mathrm{KJ} / \mathrm{s}$

$O P=\frac{T_{\text {cold }}}{T_{\text {hot }}-T_{\text {cold }}}=\frac{0+273}{(22+273)-(0+273)}=\frac{273}{293-273}=\frac{273}{20}=13.65$

$C O P=\frac{Q_{\text {cold}}}{w}=>13.65=\frac{2.2}{w} W=\frac{2.2}{13.65}=0.161 \mathrm{KJ} / \mathrm{s}=161 \mathrm{W}(0.1 \mathrm{KJ} / \mathrm{s}=100 \mathrm{W})$

Thus we can say that <em>minimum power required by refrigerator if a refrigerator removes heat to an environment at 20°C from a refrigerated space at 0°C at 2.2 kJ/s is 161W.</em>

5 0

3 years ago

Multilane roads use what to divide lanes of traffic moving in the same direction.

Rina8888 [55]

Answer:

broken white lines

4 0

3 years ago

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A BS of 5.43 ft is taken on a level rod at a 120-ft distance, and a FS of 8.76 ft is taken on the rod held 1,100 feet away.(a) W

jok3333 [9.3K]

Answer: