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r-ruslan [8.4K]
3 years ago
6

One hundred grams of water is saturated with NH CI at

Chemistry
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

  • About 18 g of NH₄Cl will precipitate.

Explanation:

The <em>table G</em> is the graph of the solubility curves for several solutes which is attached.

The second picture identifies the solubilities for the  NH₄Cl at 50ºC and 10ºC.

The solubility of NH₄Cl at 50ºC is about 52 g/ 100 g of water.

The solubility of NH₄Cl at 10ºC is about 34 g / 100 g of water.

Then, at 50ºC 100 g of water saturated with NH₄Cl contains about 52 g of NH₄Cl and 100 g of water saturated with NH₄Cl contains 34 g of NH₄Cl.

The difference, 52g - 34 g of NH₄Cl shall precipitate:

          52 g - 34 g = 18g ← answer

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HACTEHA [7]

Answer:

4.52 x 10¹⁴ cycles/s

Explanation:

From c = f·λ => f = c/λ = (3.0 x 10⁸ m/s)/(6.63 x 10⁻⁷m) = 4.52 x 10¹⁴ cycles/s.

f = frequency = ?

λ = wavelength = 6.63 x 10⁻⁷ meter

c = speed of light in vacuum = 3.0 x 10⁸ meters/s

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3 years ago
How many grams are there in 5.00 moles of lead
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White blood cells called B cells produce proteins that can be used for the treatment of certain illnesses. However, these B cell
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Explanation:

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3 0
3 years ago
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4 0
3 years ago
Do anyone know how to do question B
Over [174]

Answer:

a) IUPAC Names:

                   1) (<em>trans</em>)-but-2-ene

                   2) (<em>cis</em>)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

7 0
2 years ago
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