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CaHeK987 [17]
3 years ago
10

You throw a ball vertically upward, and as it leaves your hand, its speed is 10.0 m/s.

Physics
1 answer:
8090 [49]3 years ago
5 0
The answer is A bc I did the quiz and I got it right
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How much work is accplished when a force of 250 n pushes a box accross the floor for a distance of 50 meters
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You just multiply these two numbers, it's 1250J
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What is a relatively soft layer of upper mantle called?
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The answer is asthenosphere

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A "gauge 8" jumper cable has a diameter d of 0.326 centimeters. The cable carries a current I of 30.0 amperes. The electric fiel
AveGali [126]

Answer:

0.0979 N/c

Explanation:

Electric field, E is given as a product of resistivity and current density

E=jP where P is resistivity and j is current density

But the current density is given as

j=\frac {I}{A} where I is current and A is area and A=\pi r^{2}

Substituting this into the first equation then E=P\times \frac {I}{\pi r^{2}}

Given diameter of 0.259 cm= 0.00259 m and the radius will be half of it which is 0.001295 m

E=1.72\times 10^{-8}\times \frac {30}{\pi \times 0.001295^{2}}=9.79\times 10^{-2} N/c=0.0979 N/c

4 0
3 years ago
HURRY The compressed spring of a dart gun has potential energy of 50 J. If the spring constant is 200 N/m, what is the displacem
Crank
Spring potential energy:
E = 0.5 * k * x²

k spring constant
x spring compression

x = √(2 * E / k) = 0.7


7 0
3 years ago
Read 2 more answers
The acceleration due to gravity is 9.81 m/s2, towards the Earth. Rain falling from an altitude of 9,000 m would fall for about 1
Anna [14]

Answer:

the final speed of the rain is 541 m/s.

Explanation:

Given;

acceleration due to gravity, g = 9.81 m/s²

height of fall of the rain, h = 9,000 m

time of the rain fall, t = 1.5 minutes = 90 s

Determine the initial velocity of the rain, as follows;

h = ut + \frac{1}{2} gt^2\\\\9000 = 90u +  \frac{1}{2} (9.8)(90)^2\\\\9000 = 90u + 39690\\\\90u = -30690\\\\u = \frac{-30690}{90} \\\\u = -341 \ m/s

The final speed of the rain is calculated as;

v^2 = u^2 + 2gh\\\\v^2 = (-341)^2 + 2(9.8\times 9000)\\\\v^2 = 292681\\\\v = \sqrt{292681} \\\\v = 541 \ m/s

Therefore, the final speed of the rain is 541 m/s.

3 0
3 years ago
Read 2 more answers
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