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rosijanka [135]
3 years ago
14

When matter changes from one state to another, what do we call this process? A. a physical change B. a nuclear change C. an expl

osion D. chemical bonding
Physics
2 answers:
Contact [7]3 years ago
7 0

So it's going to be physical change

klemol [59]3 years ago
3 0
A. physical change

 Look at the way water freezes and  changes to ice<span>. The matter is still going to be the same. its just the physical property that changed.

<u>PHYSICAL= TEMPORARY</u>
<u>CHEMICAL= PERMANENT</u></span>
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A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?
dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle a=10m/sec^2

We have to find the radius of the circle

We know that acceleration is given by a=\frac{v^2}{r}

So 10=\frac{5^2}{r}

r=\frac{25}{10}=2.5m

So radius of the circle will be 2.5 m

3 0
3 years ago
If you ride your bike 20 miles and it takes you 120 minutes,what is your average speed
Alexus [3.1K]
120 minutes=2 hours
20/2= 10mph
5 0
3 years ago
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6 0
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A race car has a maximum speed of 0.104 km/s .What is this speed in miles per hour ?
sweet [91]

Answer:

232.641374 mph

Explanation:

A race car has a maximum speed of 0.104km/s

Let X represent the speed in miles per hour

Therefore the speed in miles per hour can be calculated as follows

1 km/s = 2,236.936292 mph

0.104km/s = X

X = 0.104 × 2,236.936292

X = 232.641374

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8 0
3 years ago
A circuit consists of one 330 ohm resistor in series with two other resistors (470 ohms and 220 ohms) connected in parallel. Wha
umka21 [38]

Answer:

power drain on an ideal battery, P = 0.017 W

Given:

R_{1} = 330\ohm

R_{2} = 470\ohm

R_{3} = 220\ohm

Since, R_{2} = 470\ohm and R_{3} = 220\ohm are in parallel and this combination is in series with R_{1} = 330\ohm, so,

Equivalent resistance of the circuit is given by:

R_{eq} = \frac{R_{2}R_{3}}{R_{2} + R_{3}} + R_{1}

R_{eq} = \frac{470\times 220}{470 + 220} + 330

R_{eq} = 149.85 + 330 = 479.85 \ohm

power drain on an ideal battery, P = \frac{V^{2}}{R_{eq}}

                                                      P = \frac{2.9^{2}}{479.85}

                                                      P = 0.017 W

4 0
3 years ago
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