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3 years ago

Chemical bonds contain energy that can be released when they are broken. True False

Chemistry

2 answers:

faust18 [17]3 years ago

7 0

The answer ox Falseeeeeeee......

Ilia_Sergeevich [38]3 years ago

7 0

The statement above is FALSE.

Chemical bonds do not contain energy that can be released when they are broken. In chemical reactions, bonds are typically broken and re-arrange in order to form new products. Energy is normally needed to break existing chemical bonds and energy is released when new chemical bonds are formed. Although energy is involved in breaking and forming of chemical bonds, the chemical bonds themselves are devoid of energy.

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Identify the classification of whipped cream. group of answer choices aerosol solid aerosol foam emulsion solid emulsion

skelet666 [1.2K]

The classification of whipped cream is a foam.

So, option C is correct one.

The whipped cream is a colloid and it consists of gas ( dispersed phase ) in liquid ( dispersed medium) system.

Sol is a solid dispersed in the liquid . Examples includes Au , S sol in water , milk of magnesia .

The emulsion is liquid dispersed into the liquid . Example is milk

Foam is a gas dispersed into the liquid . Examples includes whipped cream , shaving cream , foam on the beer .

Gel is the liquid dispersed into the solid . Examples includes , butter , jellies .

To learn more about colloid

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1 year ago

You have a friend who has decided to start a facility that generates

uranmaximum [27]

Answer:

should be Anaerobic Digestion

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3 years ago

Use Table 1: Analysis of Decay in the laboratory guide to answer this question: Scientists find a piece of wood that is thought

Sladkaya [172]

<span>We are given the initial amount of 1 million carbon-14 atoms and the final amount which is 1/16 of the current atmospheric 14C levels. Also, the half life of carbon is </span>5,750 years. WE can use the decay formula

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1,000,000(1/16) = (1,000,000)e^-(ln2/5750)t
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3 years ago

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Tresset [83]

First option.

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3 years ago

Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o

Gnom [1K]

Answer: The empirical formula for the given compound is $C_5H_7N$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

$C_xH_yN_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of $CO_2=21.363mg=21.363\times 10^3g=21363g$

Mass of $H_2O=6.125g=6.125\times 10^3g=6125g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, $\frac{12}{44}\times 21363=5826.27g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, $\frac{2}{18}\times 6125=680.55$ of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = $\frac{485.52}{97.73}=4.96\approx 5$

For Hydrogen = $\frac{680.55}{97.73}=6.96\approx 7$

For Nitrogen = $\frac{97.73}{97.73}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is $C_5H_7N_1=C_5H_7N$

7 0

3 years ago