Answer: Warm ocean air then rises into the storm, then forming an area of low pressure underneath. :)
Explanation:
Answer:
active transport requires energy and passive transport does not require energy
Explanation:
C
A has 2H 2O on the left and 4H 2O on the right
B has 4H 4O on the left and 4H 2O on the right
D has 2H 2O on the left and 2H 4O on the right
C has 2H 2O and 2H 2O so is balanced.
The two bulges are called tidal bulges. There are two
tidal bulges on opposite sides of Earth. One is beneath the moon and the
other is opposite to that. The one below the moon is thought of as gravitational.
It is produced by gravitational attraction between water molecules in the ocean
and the moon.
<span>Now, about the other bulge. Think about inertia and what
happens when masses rotate around a single point. Imagine yourself
swinging a bucket of any liquid with your arm in a circular gesture. Even as
the bucket goes over your head, the water is still held in the bucket and
doesn't splash all over you. This rotation creates a centrifugal force. A
similar event occurs during the lunar month as the earth/moon system rotates. The
moon orbits the earth, but the rotation axis for this orbit isn't earth's
center. Both the moon and Earth move during the roughly 28-day period it takes
for the orbit, and because of this, water in the ocean is thrown to the
outside, the same as the water in your bucket. The tidal bulge on the opposite
side of Earth from the moon is produced by this inertial effect, referred to as
centrifugal force.</span>
The mass of silver chloride produced is 24.79g.
Given,
volume = 1.11 L
Molarity = 0.156 M
First, convert molarity to moles by multiplying by the volume:
0.156 M AgNO3 = (0.156 moles AgNO3)/1 L x 1.11 L = 0.173 moles AgNO3
We are only interested in AgCl, not AgNO3. We convert moles of silver nitrate to moles of silver chloride using the balanced equation. This is a 1:1 conversion:
0.173 moles AgNO3 x (1 mole AgCl)/(1 mole AgNO3) = 0.173 moles AgCl
To get mass from moles, we multiply by the molar mass:
0.173 moles AgCl x (143.32 g/mol) = 24.79 g AgCl
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