Answer:
38.4 mol LiOH
Explanation:
Step 1: Write the balanced neutralization equation
2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.
Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂
19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH
The H+ in a solution that has a Ph of 8.73 is calculate as follows
Ph is always = - log (H+)
H+ = 10^-Ph
H+ is therefore = 10 ^- 8.73
H+ = 1.86 x10^-9 M
Answer:
Exothermic reaction.
Explanation:
From the question given, we obtained the following:
The equation for the reaction:
A —> C
From the diagram given in the question above, the reactant, A has a higher energy than the product, C. This simply indicates exothermic reaction as the enthalphy change, ΔH will be negative for the reaction.
Enthalpy change, ΔH is simply the difference between the heat of product, Hp and the heat of reactant, Hr i.e
ΔH = Hp – Hr
Since the heat of the product is small, the enthalphy change, ΔH will be negative indicating that heat has be released to the surroundings. This is termed exothermic reaction.
