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2 years ago

Need some help with these problems please.

Mathematics

1 answer:

goldenfox [79]2 years ago

3 0

Answer:

See below.

Step-by-step explanation:

Divide the leading terms:

6x^4 / 2x^2 = 3x^2

3x2 is a parabola so the long run is

as x ---> +/- infinity r(x) ----> + infinity. (answer).

10,000x^3 / 50 x^3

= 200.

So r(x) as a horizontal asymptote at y ( r(x)) = 200. (answer).

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Choose the correct equation to represent the problem and solve. apollo purchased a four pack of 50-watt light bulbs. he then bou

Step2247 [10]

66 = 4 + 8v - 2 <== ur equation
66 = 2 + 8v
66 - 2 = 8v
64 = 8v
64/8 = v
8 = v <=== there are 8 bulbs in each value pack

5 0

2 years ago

How do you solve |3x|=18

Oduvanchick [21]

We can get two different equations from this:

3x = 18

and

3x = -18

So:

x = 6, x = -6

x = {6, -6}

6 0

2 years ago

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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8

vredina [299]

Question:

Consider the sequence of numbers: $\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

$f(n + 1) = f(n) + \frac{3}{8} .$

Explanation:

A sequence of numbers are

$\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Let us first change mixed fraction into improper fraction.

$\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}$

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

$\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}$

$\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}$

$\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}$

$\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}$

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding $\frac{3}{8}$ to the previous term.

Hence, the sequence is recursive and can be represented by the function $f(n + 1) = f(n) + \frac{3}{8} .$

3 0

2 years ago

F(x)=x^2-9x+2 evaluate f(-2)

Anton [14]

I believe is your answer
Because u plug in -2 to all x
F(x)= (-2)^2-9(-2)+2
F(x)=4+18+2
F(x)=24

4 0

2 years ago

Solve by factoring:

DerKrebs [107]

A.(x+3)(x+4)=0
x=-3,-4
B.X=5,4
hope this helps

7 0

2 years ago

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