Hi there!
This collision is an example of an inelastic collision since kinetic energy is lost from the collision.
We can represent this using the conservation of momentum formula:
m1v1 + m2v1 = m1vf + m2vf
Where:
m1 = blue ball
m2 = green ball
We know that the final velocity of the blue ball is 0, so:
m1v1 + m2v1 = m2vf
Rearrange to solve for the speed of the green ball:
(m1v1 + m2v1)/m2 = vf
Plug in given values:
((0.15 · 3) + (0.15 · 2)) / 0.15 = 5 m/s
Remember opposites attract and same charges repel each other.
Object A= negatively charged.
Object A and B attract so B must be positively charged.
Object B and C repel so because B is positively charged C must also be positively charged.
Object C and D attract and because C is positively charged, D must be negatively charged.
Answer:
0.71121 km/s
Explanation:
= Velocity of planet initially = 54 km/s
= Distance from star = 0.54 AU
= Final velocity of planet
= Final distance from star = 41 AU
As the angular momentum of the system is conserved
When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.
You have a photo? I could help you if you show me a picture!
