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3 years ago

A. Fill in the blanks in the following paragraph to correctly identify some

Physics

2 answers:

amid [387]3 years ago

7 0

Answer:

1.) Liquid

2.) Low

3.) Molecular

4.) Surface tension

5.) Solvent

Explanation:

Water is important to living things because it remains in the LIQUID state over a wide range of temperatures. Water in lakes and oceans does

not experience large temperature changes because liquid water has a

LOW specific heat, so it must absorb or release a lot of energy as its temperature changes. The MOLECULAR forces between water

molecules cause water to form round droplets and cause water's high SURFACE TENSION. Water is also an important SOLVENT because it can

dissolve many different substances.

STALIN [3.7K]3 years ago

5 0

Answer:

1) liquid

2) high

3) cohesive

4) surface tension

5) solvent

Explanation:

the other person got 3 and 4 wrong

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A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta

jeyben [28]

Answer:

$V_0$

Explanation:

Given that, the range covered by the sphere, $M$ , when released by the robot from the height, $H$ , with the horizontal speed $V_0$ is $D$ as shown in the figure.

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So, if the time of flight is $t$ , then

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$s=ut+\frac 1 2 at^2\;\cdots (ii)$

Where $s$ is the displacement is the direction of force, $u$ is the initial velocity, $a$ is the constant acceleration and $t$ is time.

Here, $s= -H, u=0,$ and $a=-g$ (negative sign is for taking the sigh convention positive in $+y$ direction as shown in the figure.)

So, from equation (ii),

$-H=0\times t +\frac 1 2 (-g)t^2$

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Similarly, for the launched height $2H$ , the new time of flight, $t'$ , is

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From equation (iii), we have

$\Rightarrow t'=\sqrt 2 t\;\cdots (iv)$

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Let, the distance covered in the $x-$ direction be $D_1$ for $V_0$ and $D_2$ for $2V_0$ , we have

$D_1=V_0t'$

$D_1=V_0\times \sqrt 2 t$ [from equation (iv)]

$\Rightarrow D_1=\sqrt 2 D$ [from equation (i)]

$\Rightarrow D_1=1.41 D$ (approximately)

This is in the $3$ points range as given in the figure.

Similarly, $D_2=2V_0t'$

$D_2=2V_0\times \sqrt 2 t$ [from equation (iv)]

$\Rightarrow D_2=2\sqrt 2 D$ [from equation (i)]

$\Rightarrow D_2=2.82 D$ (approximately)

This is out of range, so there is no point for $2V_0$ .

Hence, students must choose the speed $V_0$ to launch the sphere to get the maximum number of points.

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MakcuM [25]

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Answer:

The momentum would be doubled

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The magnitude of the momentum of the freight train is given by:

$p=mv$