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mestny [16]
3 years ago
13

A WLAN transmitter that emites a 100 mW signal is connected to a cable with a 3dB loss. If the cable is connected to an antenna

with 7 dBi of gain, what is the EIRP at the antenna element?

Physics
1 answer:
irakobra [83]3 years ago
6 0

Answer: 24 dBm

Explanation:

in the attachment

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If the mass of both objects are doubled while the
lutik1710 [3]

Answer:

The force becomes 16 times what it is now.

Explanation:

The formula for gravitational force is

F = G * m1 * m2 / r^2

When you do what you have described, you are setting a stage that not even the USS Enterprise (Star Trek) can get out of. The increase is huge.

If you double m1 and m2 and don't do anything to r, you've already increased the force by 4 times. (2m1 * 2m2 = 4 * m1 * m2)

But you are not finished. If you 1/2 the distance, you are again increasing the Force by 4 times. 1 / (2r) ^2 = 1/ 4* r^2

Because this is in the denominator, the 1/4 is going to flip to the numerator.

So the total increase is going to be 4 * (4 * m1 * m2) = 16 * m1 * m2.

Think about what that means. If you were out golfing, your drives would be roughly 1/16 times as far as they are now. Also you would be lugging around 16 times your weight around the golf course. My feeling is that you would never finish 5 holes at that rate.

3 0
2 years ago
When the mass of an object decreases, the force of gravity - Remains Unchanged - Decreases - increases - Becomes irregular
Gwar [14]
The force of gravity decreases
5 0
3 years ago
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AlekseyPX
Friction is caused by the uneven surfaces of touching objects
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2 years ago
What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
Yuki888 [10]

Explanation:

825m/s / 1.8Hz = 458.33m

6 0
2 years ago
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For a ∆x of 0.1mm, what is ∆px, the uncertainty in the transverse momentum of a photon passing through a slit (where uncertainty
Colt1911 [192]

Answer:

0.53\times 10^{-30}kgms^{-1}

Explanation:

Uncertainty principle say that the position and momentum can not be measured simultaneously except one relation which is described below,

\Delta x\Delta p=\frac{h}{4\pi }

Given that the uncertainty in x is 0.1 mm.

Therefore,

\Delta p=\frac{6.626\times 10^{-34} }{4\times 3.14\times 1\times 10^{-4}m }\\\Delta p=0.53\times 10^{-30}kgms^{-1}

Therefore, uncertainty in the transverse momentum of photon is 0.53\times 10^{-30}kgms^{-1}

6 0
2 years ago
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