To solve this question, we will use Graham's law which states that:
(R1 / R2) ^ 2 = M2 / M1 where
R1 and R2 are the rates of effusion and M1 and M2 are the molar masses of the two gases.
From the periodic table, we can calculate the molar mass of O2 as follows:
molar mass of O2 = 2*16 = 32 grams
Therefore we have:
R1 / R2 = Ry / RO2 = 1/2
M1 is My we want to get
M2 is molar mass of O2 = 32 grams
Substitute in the above equation to get the molar mass of y as follows:
(1/2) ^2 = (32/My)
1/4 = 32/My
My = 32*4 = 128
Therefore, molar mass of gas y = 128 grams
11.19%. This should be right. I have no doubt that you will get it right.
Answer:
P = 741.7 Pa
Explanation:
Pressure:
It is the force applied on object per unit area. The force is applied perpendicular to the surface.
Mathematical expression:
P = F/A
P = pressure
F = force
A = area
Given data:
Weight = 178 N
Area = 10 cm × 24 cm
Pressure = ?
Solution:
Area = 10 cm × 24 cm
Area = 240 cm²
Area = 240 /10000 = 0.024 m²
Formula:
P = F/A
P = 178 N / 0.024 m²
P = 741.7 Nm⁻²
Nm⁻² = Pa
P = 741.7 Pa
<u>Answer:</u> The boiling point of solution is 101.56°C
<u>Explanation:</u>
Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.
The equation used to calculate elevation in boiling point follows:
To calculate the elevation in boiling point, we use the equation:
Or,
where,
Boiling point of pure water = 100°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal boiling point elevation constant = 0.52°C/m.g
= Given mass of solute (urea) = 27.0 g
= Molar mass of solute (urea) = 60 g/mol
= Mass of solvent (water) = 150.0 g
Putting values in above equation, we get:
Hence, the boiling point of solution is 101.56°C
Answer: the mass of the object
Explanation: To find density, the equation d= m/v is needed where m= mass and v= volume
