A stretched rubber band is storing <em>elastic potential energy. (A)</em>
<u>Answer:</u>
The ball is rolling at a speed of 0.02 meter per second.
<u>Step by step explanation:</u>
We are given that there is a 800 gram bowling ball rolling in a straight line. If its momentum is given to be 16 kg.m/sec, we are to find its velocity.
For this, we will use the formula of momentum.
<em>Momentum = mass × velocity</em>
16 = 800 × velocity
Velocity = 16/800 = 0.02 meter per second
Answer:
61440 peaks
Explanation:
A hertz represents one cycle for every second:

So if a wave have frequency of 2Hz for example, this means the wave does two cycles per second.
Normally the waves are represented by cosine or sine waves. These kind of waves have two peaks in each cycle, one positive and one negative. With this in mind, let's calculate how many peaks of the wave pass each minute.
A minute has 60 seconds, hence:

And we know already that every cycle has two peaks, so:

The pressure value is given by the equation,

Where,
represents the density of the liquid
g= gravity
h= Heigth
A) For the measurement of the guage pressure we have the data data,



Replacing we get,

P_g = 12395Pa[/tex]
In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,
B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

For a cylinder that has both ends open resonant frequency is given by the following formula:

Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:

To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:

We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:

Since n has to be an integer, final answer would be 323.