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nasty-shy [4]
3 years ago
11

How do you reconcile the law of falling bodies (that all objects fall to earth at the same acceleration despite their weight) wi

th the Second Law of Motion which states that the acceleration of a body subjected to an applied force is inversely proportional to its mass?
Physics
1 answer:
ASHA 777 [7]3 years ago
5 0

From the gravity acceleration theorem due to a celestial body or planet, we have that the Force is given as

F = \frac {GMm} {r ^ 2}

Where,

F = Strength

G = Universal acceleration constant

M = Mass of the planet

m = body mass

r = Distance between centers of gravity

The acceleration by gravity would be given under the relationship

g = \frac {F} {m}

g = \frac {GM} {r ^ 2}

Here the acceleration is independent of the mass of the body m. This is because the force itself depended on the mass of the object.

On the other hand, the acceleration of Newton's second law states that

a = \frac {F} {m}

Where the acceleration is inversely proportional to the mass but the Force does not depend explicitly on the mass of the object (Like the other case) and therefore the term of the mass must not necessarily be canceled but instead, considered.

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Brut [27]
If ur meaning cavins. a cavin is like a cave or a hollow route.      idk if thats what ur asking?
5 0
2 years ago
how do you Compute the approximate acceleration of gravity for an object above the earth's surface, assigning accel gravity with
solong [7]

The approximate acceleration of gravity for an object above the earth's surface is 9.8 m/s².

<h3>Acceleration due to gravity </h3>

The acceleration due to gravity of an object above the Earth's surface is calculated from Newton's second law of motion and Newton's law of universal gravitation.

<h3>Force between the object and Earth</h3>

F_g = \frac{GmM}{R^2}

<h3>Weight of the object</h3>

F_g = mg\\

Solve (1) and (2)

mg = GmM/R²

g = GM/R²

where;

  • M is mass of Earth
  • G is gravitational constant
  • R is radius of the Earth = 6,371 km

g = (6.673 x 10⁻¹¹ x 5.98 x 10²⁴)/(6,371 x 10³)²

g = 9.8 m/s²

Learn more about acceleration due to gravity here: brainly.com/question/88039

#SPJ1

7 0
2 years ago
How many (whole number of) 91 kg people
Tcecarenko [31]

We are given that the maximum mass capacity is 1 metric ton or 1000 kg. Therefore the amount of people this can hold is simply the ratio of the maximum mass capacity over the mass of the person, that is:

people = 1000 kg / 91 kg

people = 10.98

 

So the elevator can safely occupy 10 people. We will not exceed to 11.

6 0
3 years ago
Read 2 more answers
How much is the tension number 2
mestny [16]

This is what I got:

Net force in the Y direction:

ΣFy = T1 - T2

F = ma

ma = T1 - T2

Isolate for T2

ma - T1 = -T2

Multiply by -1

T1 - ma = T2

100 - (3)(2) = T2

100 - 6 = T2

T2 = 94 N

4 0
3 years ago
I dont know what pfp to put on today so I'm asking u guys....
Mandarinka [93]

Answer:

i think number 2 should be your pfp

5 0
2 years ago
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