1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VikaD [51]
3 years ago
6

During the experiment if you could double the breakaway magnetic force with all other quantities left unchanged, what is the new

value for the critical velocity if it was vo initially?
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0
There are some missing information in the question.
However, since you are talking about magnetic force, I think you refer to the Lorentz force. When a particle of charge q and velocity v is immersed in a magnetic field of intensity B, the force acting on the particle is:
F=qvBsin\theta
where \theta is the angle between the magnetic field and the direction of the particle.
Therefore, if force F is doubled, then also the velocity v must be double of its initial value:
v=2v_0
You might be interested in
Which of the following is true concerning atoms?Atoms are made of even smaller substances called subatomic particles
olasank [31]
The correct answer of the given question above would be the first option. The statement that is true concerning atoms is that, atoms are made of even smaller substances called subatomic particles. Subatomic particles include neutrons, protons, electrons and atomic nuclei. Hope this answer helps. 
3 0
3 years ago
A cable raises a mass of 198.0 kg with an acceleration of 1.2 m/s2. What force (in N) of tension is in the cable
PilotLPTM [1.2K]

Answer:6ygmfghgggyo76

Explanation:

4 0
2 years ago
The diagram below shows a circuit with a
kirill [66]

Answer:

15v

Explanation:

V = IR

= 0.3*50

= 15V.

I HOPE IT'S HELPFUL

4 0
2 years ago
On a planet where g = 10.0 m/s2 and air resistance is negligible, a sled is at rest on a rough inclined hill rising at 30°. The
Cloud [144]

Answer:

Explanation:

a is the acceleration

μ is the coefficient of friction

Acceleration of the object is given by

a = g (\sin  \theta -\mu \cos \theta)\\\\=10( \sin 30 - 0.4 \cos 30)\\\\=10(0.5-0.3464)\\\\=1.54m/s^2

Velocity at the bottom

v^2=u^2+2as\\\\u=0\\\\v^2=2as\\\\=2*1.54*8\\\\=24.576\\\\v=4.96m/s

after travelling 4m , its velocity becomes 0

a=\frac{v^2-u^2}{2s}

a=\frac{0-u^2}{2s}

a=\frac{-(-4.96)^2}{2*4} \\\\=-3.075m/s^2

Coefficient of kinetic friction

μ = F/N

=\frac{ma}{mg} \\\\=\frac{3.075}{10} \\\\=0.31

Therefore, the Coefficient of kinetic friction is 0.31

8 0
2 years ago
Read 2 more answers
4.5 x 10kg) - (2.3 x 10 kg)
Degger [83]

Answer:

22 kg

Explanation:

I hope this helps!

6 0
3 years ago
Read 2 more answers
Other questions:
  • The angle turned through the flywheel of a generator during a time interval t is given by theta = at + bt^3 -ct^4, where a, b, a
    12·1 answer
  • Derivative of arcsin(cos(2x))<br> is this chain rule?
    14·1 answer
  • The moon is about 3.8 X 10^5 km from the earth. Show that its average orbital speed about earth is 1026 m/s
    14·1 answer
  • Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k
    9·1 answer
  • What happens when a muscle contracts
    13·1 answer
  • A (11.4 A) ohm device is connected to a 115 V outlet. If the cost of the electrical energy is $0.16/kWh, determine the cost of r
    15·1 answer
  • Find the 7th term of the geometric sequence<br>1/8, 1/2, 2, ...<br>​
    10·1 answer
  • A mass, M, is at rest on a frictionless surface, connected to an ideal horizontal spring that is unstretched. A person extends t
    8·1 answer
  • A student has been assigned to measure the density of an irregularly shaped piece of metal.which apparatus would be more appropr
    12·1 answer
  • A lamp draws a current of 20 A when it is connected to a 100 V source? What is the resistance of the lamp?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!