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VikaD [51]
3 years ago
6

During the experiment if you could double the breakaway magnetic force with all other quantities left unchanged, what is the new

value for the critical velocity if it was vo initially?
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0
There are some missing information in the question.
However, since you are talking about magnetic force, I think you refer to the Lorentz force. When a particle of charge q and velocity v is immersed in a magnetic field of intensity B, the force acting on the particle is:
F=qvBsin\theta
where \theta is the angle between the magnetic field and the direction of the particle.
Therefore, if force F is doubled, then also the velocity v must be double of its initial value:
v=2v_0
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Two 10-cm-diameter charged rings face each other, 25 cm apart. The left ring is charged to ? 25 nC and the right ring is charged
MArishka [77]

Answer:

A)   E = 0N/C

B)   0i + 0^^j

C)   F = 0N

D)   0^i  + 0^j

Explanation:

You assume that the rings are in the zy plane but in different positions.

Furthermore, you can consider that the origin of coordinates is at the midway between the rings.

A) In order to calculate the magnitude of the electric field at the middle of the rings, you take into account that the electric field produced by each ring at the origin is opposite to each other and parallel to the x axis.

You use the following formula for the electric field produced by a charge ring at a perpendicular distance of r:

E=k\frac{rQ}{(r+R^2)^{3/2}}               (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C

Q: charge of the ring

r: perpendicular distance to the center of the ring

R: radius of the ring

You use the equation (1) to calculate the net electric field at the midpoint between the rings:

E=k\frac{rQ}{(r^2+R^2)^{3/2}}-k\frac{rQ}{(r^2+R^2)^{3/2}}=0\frac{N}{C}

The electric field produced by each ring has the same magnitude but opposite direction, then, the net electric field is zero.

B) The direction of the electric field is 0^i + 0^j

C) The magnitude of the force on a proton at the midpoint between the rings is:

F=qE=q(0N/C)=0N

D) The direction of the force is 0^i + 0^j

6 0
3 years ago
A balloon is filled with a gas at 111 kPa when the temperature was 22*C. If the temperature
storchak [24]

119.7kPa

Explanation:

Given parameters:

Pressure of gas in balloon = 111kPa

Temperature of gas = 22°C

Final temperature = 45°C

Unknown:

Final pressure = ?

Solution:

Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.

At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.

           \frac{P1}{T1}   =  \frac{P2}{T2}

P1 is the initial pressure

P2 is the final pressure

T1 is the initial temperature

T2 is the final temperature

 convert from celcius to kelvin:

       tK = 273 + tC

   T1 = 273 + 22 = 295K

   T2 = 273 + 45 = 318K

      \frac{111}{295}  =  \frac{P2}{318}

  P2 = 119.7kPa

learn more:

Ideal gas brainly.com/question/13064292

#learnwithBrainly

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20 degrees F! 0 degrees C is equivalent to 32 degrees F, so 20 degrees F is colder.
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A lot because of the way that the force that it would be
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Answer: B

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