The statement which best characterizes the relationship between a general contractor and a construction manager is that; A construction manager subcontracts a general contractor to perform <em>work</em>.
A construction project manager is saddled with the responsibility of overseeing the planning and delivery of construction projects.
- In essence, they ensure that work is completed on time and within budget. Other functions include organising logistics, delegation of work and tracking of spending.
A general contractor otherwise known as the prime contractor is responsible for the day-to-day oversight of a construction site,<em> employment of labour, management of vendors and trades, and most importantly, the communication of information to all involved parties throughout the course of a building project.</em>
- <em>Ultimately</em><em>,</em><em> </em><em>the </em><em>relationship</em><em> </em><em>between</em><em> </em><em>a </em><em>general contractor and a construction manager is that; A construction manager subcontracts a general contractor to perform work.</em>
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R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
Correct Answer:
A. water pump
Explanation:
<em>Timing belt in a vehicle helps to ensure that crankshaft, pistons and valves operate together in proper sequence.</em> Timing belts are lighter, quieter and more efficient than chains that was previously used in vehicles.
<em>Most car manufacturers recommended that, when replacing timing belt, tension assembly, water pump, camshaft oil seal should also be replaced with it at same time. </em>
Answer:
a) at T = 5800 k
band emission = 0.2261
at T = 2900 k
band emission = 0.0442
b) daylight (d) = 0.50 μm
Incandescent ( i ) = 1 μm
Explanation:
To Calculate the band emission fractions we will apply the Wien's displacement Law
The ban emission fraction in spectral range λ1 to λ2 at a blackbody temperature T can be expressed as
F ( λ1 - λ2, T ) = F( 0 ----> λ2,T) - F( 0 ----> λ1,T )
<em>Values are gotten from the table named: blackbody radiati</em>on functions
<u>a) Calculate the band emission fractions for the visible region</u>
at T = 5800 k
band emission = 0.2261
at T = 2900 k
band emission = 0.0442
attached below is a detailed solution to the problem
<u>b)calculate wavelength corresponding to the maximum spectral intensity</u>
For daylight ( d ) = 2898 μm *k / 5800 k = 0.50 μm
For Incandescent ( i ) = 2898 μm *k / 2900 k = 1 μm
