Explanation:
Torque is the cross product of the radius vector and force vector:
τ = r × F
In other words, it is equal to the radius times the perpendicular component of the force.
τ = r · Ftangential
If we call θ the angle between the radius and the force, then:
τ = r · F sin θ
Answer: c fine sand aggregate, portland cement,fine sand
Explanation:
Answer:
M_c = 61.6 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two casesshown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *88
M_c = 2.5*( 42 / 150 ) *88
M_c = 61.6 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.