Answer:
<em>The first law states that</em> every planet describes an elliptical path about the sun as a single focus.
<em>The</em><em> </em><em>second</em><em> </em><em>law</em><em> </em><em>states</em><em> </em><em>that</em><em> </em>The line joining the planet to the sun sweeps out equal areas in equal time intervals.
<em>The</em><em> </em><em>third</em><em> </em><em>law</em><em> </em><em>states</em><em> </em><em>that</em><em> </em>The squares of the period of revolution is proportional to the cubes of the mean distance between the planet and the sun
Explanation:
Given that,
Linear speed of both disks is 5 m/s
Mass of disk 1 is 10 kg
Radius of disk 1 is 35 cm or 0.35 m
Mass of disk 2 is 3 kg
Radius of disk 2 is 7 cm or 0.07 m
(a) The angular velocity of disk 1 is :
![v=r_1\omega_1\\\\\omega_1=\dfrac{v}{r_1}\\\\\omega_1=\dfrac{5}{0.35}\\\\\omega_1=14.28\ rad/s](https://tex.z-dn.net/?f=v%3Dr_1%5Comega_1%5C%5C%5C%5C%5Comega_1%3D%5Cdfrac%7Bv%7D%7Br_1%7D%5C%5C%5C%5C%5Comega_1%3D%5Cdfrac%7B5%7D%7B0.35%7D%5C%5C%5C%5C%5Comega_1%3D14.28%5C%20rad%2Fs)
(b) The angular velocity of disk 2 is :
![v=r_2\omega_2\\\\\omega_2=\dfrac{v}{r_2}\\\\\omega_2=\dfrac{5}{0.07}\\\\\omega_2=71.42\ rad/s](https://tex.z-dn.net/?f=v%3Dr_2%5Comega_2%5C%5C%5C%5C%5Comega_2%3D%5Cdfrac%7Bv%7D%7Br_2%7D%5C%5C%5C%5C%5Comega_2%3D%5Cdfrac%7B5%7D%7B0.07%7D%5C%5C%5C%5C%5Comega_2%3D71.42%5C%20rad%2Fs)
(c) The moment of inertia for the two disk system is given by :
![I=I_1+I_2\\\\I=\dfrac{1}{2}m_1r_1^2+\dfrac{1}{2}m_2r_2^2\\\\I=\dfrac{1}{2}(m_1r_1^2+m_2r_2^2)\\\\I=\dfrac{1}{2}\times (10\times (0.35)^2+3\times (0.07)^2)\\\\I=0.619\ kg-m^2](https://tex.z-dn.net/?f=I%3DI_1%2BI_2%5C%5C%5C%5CI%3D%5Cdfrac%7B1%7D%7B2%7Dm_1r_1%5E2%2B%5Cdfrac%7B1%7D%7B2%7Dm_2r_2%5E2%5C%5C%5C%5CI%3D%5Cdfrac%7B1%7D%7B2%7D%28m_1r_1%5E2%2Bm_2r_2%5E2%29%5C%5C%5C%5CI%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%2810%5Ctimes%20%280.35%29%5E2%2B3%5Ctimes%20%280.07%29%5E2%29%5C%5C%5C%5CI%3D0.619%5C%20kg-m%5E2)
Hence, this is the required solution.
Answer:
<h3>25km/hr</h3>
Explanation:
Velocity is the change in displacement of a body with respect to time.
Velocity - Displacement/time
Given
displacement = 76km
Time = 3hours
Substitute the given parameters into the formula;
Velocity = 75km/3hrs
Velocity = 25km/hr
Hence the velocity of the narwhal is 25km/hr