Answer:
Radial acceleration of moon is 
 
 
Explanation:
Given :
Time period  sec
 sec
Distance from center of moon to planet  m
 m
From the equation of radial acceleration,
   
Where 
So    
 
Now moon's radial acceleration,
  
  
   
 
 
        
             
        
        
        
Answer:Probably water ballons,Paint,Etc
Explanation:
 
        
                    
             
        
        
        
Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector  

.
The positive y-axis = the northern direction, with unit vector 

.
The airplane flies at 340 km/h at 12° east of north. Its velocity vector is

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
![\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D_%7B2%7D%20%3D40%28cos%2834%5E%7Bo%7D%29%5Chat%7Bi%7D%20-%20sin%2824%5E%7Bo%7D%29%5D%5Chat%7Bj%7D%29%20%3D%2033.1615%5Chat%7Bi%7D%20-22.3677%5Chat%7Bj%7D%29)
The plane's actual velocity is the vector sum of the two velocities. It is

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h
The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°
Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.
 
        
        
        
Answer:
The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.
Explanation:
Power of toaster oven, P = 1.2 kW
Time, t = 6 minutes = 360 s
The energy used by toaster oven is given by :

Power of fluorescent light (CFL) bulb, P' = 11 W
Time, t' = 11 h = 39600 s
Energy used by fluorescent light (CFL) bulb is given by :

So, the energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.