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nexus9112 [7]
3 years ago
5

The big bang produced an imprint of leftover heat called _____. hydrogen cosmic heat CMB radiation redshift

Physics
2 answers:
maks197457 [2]3 years ago
8 0

I believe the answer you are looking for is CMB Radiation

Doss [256]3 years ago
6 0

The big bang produced an imprint of leftover heat called <u><em>CMB radiation.</em></u>


That is the answer.

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An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about
vazorg [7]

Answer:

Radial acceleration of moon is a_{r} = 2.246\times 10^{-3}\frac{m}{s^{2} }

Explanation:

Given :

Time period T = 1.987 \times 10^{6} sec

Distance from center of moon to planet r = 225 \times 10^{6} m

From the equation of radial acceleration,

  a_{r} = r\omega ^{2}

Where \omega = 2\pi f = \frac{2\pi }{T}

So   \omega = 3.16 \times 10^{-6} \frac{rad}{s}

Now moon's radial acceleration,

 a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}

 a_{r} = 2246.76 \times 10^{-6}

 a_{r} = 2.246\times 10^{-3} \frac{m}{s^{2} }

7 0
3 years ago
Who has ideas for a prank
Nimfa-mama [501]

Answer:Probably water ballons,Paint,Etc

Explanation:

3 0
3 years ago
Read 2 more answers
An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's act
seropon [69]
Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector  \hat{i}.
The positive y-axis = the northern direction, with unit vector \hat{j}.

The airplane flies at 340 km/h at 12° east of north. Its velocity vector is
\vec{v}_{1} = 340(sin(15^{o})\hat{i} + cos(15^{o})\hat{j} ) = 88\hat{i} + 328.4\hat{j}

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})

The plane's actual velocity is the vector sum of the two velocities. It is
\vec{v}=\vec{v}_{1}+\vec{v}_{2} = 121.1615\hat{i}+306.0473\hat{j}

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h

The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°

Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.
8 0
3 years ago
Compare the energy consumption of two commonly used items in the household. Calculate the energy used by a 1.20 kW toaster oven,
9966 [12]

Answer:

The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

Explanation:

Power of toaster oven, P = 1.2 kW

Time, t = 6 minutes = 360 s

The energy used by toaster oven is given by :

E=P\times t\\\\E=1.2\times 10^3\times 360\\\\E=432000\ J\\\\E=432\ kJ

Power of fluorescent light (CFL) bulb, P' = 11 W

Time, t' = 11 h = 39600 s

Energy used by fluorescent light (CFL) bulb is given by :

E'=P'\times t'\\\\E'=11\times 39600\\\\E'=435600\ J\\\\E'=435\ kJ

So, the energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

5 0
3 years ago
Protons, neutrons, and electrons are the 3 particles that make up an atom.<br> True or False
bekas [8.4K]
True

Hope that helps
4 0
3 years ago
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