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sp2606 [1]
3 years ago
7

What is the Nearest Galaxy from the Milky Way

Physics
2 answers:
vitfil [10]3 years ago
7 0
Andromeda galaxy :) hope this helps
Vsevolod [243]3 years ago
6 0

Answer:

the andromeda galaxy

Explanation:

hope it helps , pls mark me as brainliest

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3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
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does this have picture so I can solve

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What force causes a rolling ball to slow down and stop
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Newtons first law of motion or friction
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One scientist suggests that out of the different possible locations, they should design the model and build it at the equator re
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7 0
3 years ago
find the time taken, if the speed of a train increased from 72 km/hr to 90 km/hr for 234 km. leave your answer in seconds
Airida [17]

Answer:

Time taken = 10400 s

Explanation:

Given:

Initial speed of the train, u=72\textrm{ km/h}=72\times \frac{5}{18}=20\textrm{ m/s}

Final speed of the train, v=90\textrm{ km/h}=90\times \frac{5}{18}=25\textrm{ m/s}

Displacement of the train, S=234\textrm{ km}=234\times 1000=234000\textrm{ m}

Using Newton's equation of motion,

v - u = at\\a=\frac{v-u}{t}

Now, using Newton's equation of motion for displacement,

v^{2}-u^{2}=2aS

Now, plug in the value of a=\frac{v-u}{t} in the above equation. This gives,

v^{2}-u^{2}=2\times \frac{v-u}{t}\times S\\(v+u)(v-u)=\frac{2(v-u)S}{t}\\t=\frac{2(v-u)S}{(v+u)(v-u)}\\t=\frac{2S}{v+u}

Now, plug in 234000 m for S, 25 m/s for v and 20 m/s for u. Solve for t.

t=\frac{2S}{v+u}\\t=\frac{2\times 234000}{25+20}\\t=\frac{468000}{45}=10400\textrm{ s}

Therefore, the time taken by the train is 10400 s.

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4 years ago
Graphs do not need to have a title.true or false
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The answer for this question should be "false".
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3 years ago
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