All categories

3 years ago

What is the Nearest Galaxy from the Milky Way

Physics

2 answers:

vitfil [10]3 years ago

7 0

Andromeda galaxy :) hope this helps

Vsevolod [243]3 years ago

6 0

Answer:

the andromeda galaxy

Explanation:

hope it helps , pls mark me as brainliest

You might be interested in

If youre reading this goodluck in school homie <3

bazaltina [42]

I needed this ! Thanks a lot

7 0

3 years ago

Read 2 more answers

Steel is an alloy of _____. One of the main reasons steel is used more widely than iron is because it’s_____ than iron. thanks f

yarga [219]

1. Iron I think and 2. stronger

8 0

3 years ago

A wheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. Determine the constant angular acceleration and t

svetlana [45]

Answer:

(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

Explanation:

Given that,

Initial spinning = 50.0 rad/s

Time = 20.0

Distance = 2.5 m

Mass of pole = 4 kg

Angle = 60°

We need to calculate the angular acceleration

Using formula of angular velocity

$\omega=-\alpha t$

$\alpha=-\dfrac{\omega}{t}$

$\alpha=-\dfrac{50.0}{20.0}$

$\alpha=-2.5\ rad/s^2$

The angular acceleration is -2.5 rad/s²

We need to calculate the number of revolution

Using angular equation of motion

$\theta=\omega_{0}t+\dfrac{1}{2}\alpha t$

Put the value into the formula

$\theta=50\times20-\dfrac{1}{2}\times2.5\times20^2$

$\theta=500\ rad$

The number of revolution is 500 rad.

(II). We need to calculate the torque

Using formula of torque

$\vec{\tau}=\vec{r}\times\vec{f}$

$\tau=r\times f\sin\theta$

Put the value into the formula

$\tau=2.5\times4\times 9.8\sin60$

$\tau=84.87\ N-m$

Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

8 0

3 years ago

Gumuhit ng paglalaruan ng<br>agawang sulok at ibigay ang bawat<br>sukat nito.

Anarel [89]

Answer:

there's a link to answer

Explanation:

there's a link to answer in another's persons response it helps a lot just click on it

8 0

3 years ago

A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling?

Tanya [424]

Answer:

The vector sum of all forces acting on it is zero, its at equilibrium.

Explanation:

The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.

If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.

7 0

3 years ago