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hodyreva [135]
3 years ago
8

An experiment was conducted to see which metal pot would be better for cooking food quickly. The table below shows how quickly s

mall pieces of wax melted during the experiment.
Type of metal Time for the wax to melt (seconds)
Aluminum 27
Bronze 45
Copper 15
Steel 80
Chemistry
2 answers:
yuradex [85]3 years ago
5 0

Answer:

The correct answer is a conclusion.

Explanation:

Aluminum melts wax piece in 27 seconds,bronze melts it in 45 seconds where as copper and steel takes 15 seconds and 80 seconds respectively to melt a wax piece.

Increasing order of time taken by metals to melt wax:

Copper  < Aluminum < Bronze < Steel

  • If the metal takes more time to the melt the wax it means that metal requires more heat and time to get heated up to the melting point of the wax.
  • If the metal takes less time to the melt the wax it means that metal requires less heat and time to get heated up to the melting point of the wax.

So, from the order of time taken by metals to melt wax we can easily predict the metal better or suitable for  cooking food in less time and with less gain consumption of heat is copper.Hence it is a conclusion

KengaRu [80]3 years ago
3 0

Answer : It is a conclusion.

Explanation:

Conclusion: It is a judgement or decision which can be attained by reasoning.

From the observation table given we can conclude that :

  • Aluminum ,bronze and steel took 27,45 and 80 seconds to melt small piece of wax respectively which means that more time will be required by them to transfer heat to the food while cooking. Hence,  food will take more time to cook in them.
  • Copper took less time of 15 seconds to melt the small piece of wax in comparison to other metal pots which means that it is a good conductor of heat in comparison to other. Hence, copper pot would be better for cooking food quickly.

After analyzing the observations and results in an experiment conclusion was made that copper pots are best for cooking foods.

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What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

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