NO2 + H2 ----> NH3 + H2O
N(+IV) + 7e -----> N(-III) |2
H2(0) - 2e ----> 2H(+I) |7
after: 2NO2 + 7H2 ----> 2NH3 + 4H2O
I think the best answer is D
PH3
Also known as phosphine
they are all an energy particle
For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
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