Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T = ![$T_{saturated}$](https://tex.z-dn.net/?f=%24T_%7Bsaturated%7D%24)
Temperature = 120.21°C
c). Specific volume
![$v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$](https://tex.z-dn.net/?f=%24v_%7Bf%7D%3D%200.001061%2C%20%5C%20%5C%20v_g%3D0.88578%20%5C%20m%5E3%2Fkg%24)
![$v_x=v_f+x(v_g-v_f)$](https://tex.z-dn.net/?f=%24v_x%3Dv_f%2Bx%28v_g-v_f%29%24)
![$=0.001061+0.7(0.88578-0.001061)$](https://tex.z-dn.net/?f=%24%3D0.001061%2B0.7%280.88578-0.001061%29%24)
![$=0.62036 \ m^3/kg$](https://tex.z-dn.net/?f=%24%3D0.62036%20%5C%20m%5E3%2Fkg%24)
d). Specific energy (
)
![$u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$](https://tex.z-dn.net/?f=%24u_f%3D504.5%20%5C%20kJ%2Fkg%2C%20%5C%20%5C%20u_%7Bfg%7D%3D2024.6%20%5C%20kJ%2Fkg%24)
![$u_x=504.5 + 0.7(2024.6)$](https://tex.z-dn.net/?f=%24u_x%3D504.5%20%2B%200.7%282024.6%29%24)
![$=1921.72 \ kJ/kg$](https://tex.z-dn.net/?f=%24%3D1921.72%20%5C%20kJ%2Fkg%24)
e). Specific enthalpy ![$(h_x)$](https://tex.z-dn.net/?f=%24%28h_x%29%24)
At ![$h_f = 504.71, \ \ h_{fg} = 2201.6$](https://tex.z-dn.net/?f=%24h_f%20%3D%20504.71%2C%20%5C%20%5C%20h_%7Bfg%7D%20%3D%202201.6%24)
![h_x=504.71+(0.7\times 2201.6)](https://tex.z-dn.net/?f=h_x%3D504.71%2B%280.7%5Ctimes%202201.6%29)
![$= 2045.83 \ kJ/kg$](https://tex.z-dn.net/?f=%24%3D%202045.83%20%5C%20kJ%2Fkg%24)
f). Enthalpy at m = 0.5 kg
![$H=mh_x$](https://tex.z-dn.net/?f=%24H%3Dmh_x%24)
![$= 0.5 \times 2045.83$](https://tex.z-dn.net/?f=%24%3D%200.5%20%5Ctimes%202045.83%24)
= 1022.91 kJ
Answer:
The mechanical advantage is 3 to 1
Explanation:
A frictionless pulley with three support ropes carries equal tension on each of the ropes thus;
Tension in each pulley rope = T
Total tension in the 3 ropes = 3 × T = 3·T
Direction of the tension forces on each rope = Unidirectional
Total force provided by the 3 ropes = 3·T
Therefore, a force, T, applied at the end of the rope will result in a lifting force of 3·T
Hence, the mechanical advantage = 3·T to T which is presented as follows;
![Mechanical \ advantage = \dfrac{3 \cdot T}{T} = \dfrac{3}{1}](https://tex.z-dn.net/?f=Mechanical%20%5C%20advantage%20%3D%20%5Cdfrac%7B3%20%5Ccdot%20T%7D%7BT%7D%20%20%3D%20%5Cdfrac%7B3%7D%7B1%7D)
The mechanical advantage = 3 to 1.