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serg [7]
3 years ago
7

A thin, square metal plate measures 15 cm on each side and has emissivity of 0.80. The plate is heated to a temperature of 605°C

. What is the rate at which the plate radiates energy ? The Stefan-Boltzmann constant is 5.67 × 10-8 W/(m2 ∙ K4). Remember that the plate will radiate energy from both its top and bottom surfaces.
Physics
2 answers:
alexandr1967 [171]3 years ago
8 0

Answer:

1213 Watt

Explanation:

A = 15 x 15 = 225 cm^2 = 0.0225 m^2

e = 0.80

T = 605 C = 605 + 273 = 878 K

σ = 5.67 x 10^-8 W / (m2 . K^4)

Energy per unit time = σ A e T^4

Energy per unit time = 5.67 x 10^-8 x 0.80 x 0.0225 x (878)^4

Energy per unit time = 606.5 Watt

Rate of energy radiated from both the surfaces = 2 x 606.5 = 1213 Watt

Sholpan [36]3 years ago
6 0
L = 15cm = 0.15m
A = 0.15 × 0.15 = 0.0225
Sradiation is transfered from bottom
σ = 5.67 × 10⁻⁸ W/m²k
T = 605 c = 878k
Rate of energy transfer
Q = 
σ × A × E × T⁴
5.67 × 10⁻⁸ × 0.0225 × 2 × 0.8 × 878⁴
1792.17 W
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Answer:

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Explanation:

Data obtained from the question include:

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Specific heat capacity of water (Cw) = 4200J/Kg°C

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Mass of water = 1 x 200

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Mass of water = 200/1000 0.2 Kg

Mass of water = 0.2 Kg

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MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

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Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

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