As a ball falls freely toward the ground, its total <span>mechanical energy "remains the same" but it should be noted that its potential energy is decreases at this time. </span>
Answer:
The magnitude of the average induced emf in the wire during this time is 9.533 V.
Explanation:
Given that,
Radius r= 0.63 m
Magnetic field B= 0.219 T
Time t= 0.0572 s
We need to calculate the average induce emf in the wire during this time
Using formula of induce emf



.....(I)
In reshaping of wire, circumstance must remain same.
We calculate the length when wire is in two loops



The length when wire is in one loop




We need to calculate the initial area

Put the value into the formula


The final area is



Put the value of initial area and final area in the equation (I)


Negative sign shows the direction of induced emf.
Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.
Answer:
Both the frequency f and velocity v will increase.
When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.
Explanation:
The centripetal force acting on a mass in circular motion is given by equation (1);

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.
However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

Also recall that m is constant so it cancels out from both sides of equation (2). Therefore from equation we can write the following;

By observing equation (2) carefully, the ratio
will with the square root increase
since
is lesser than
.
Hence by implication, the value of
will be greater than
.
As the radius changes from
to
, the velocity also changes from
to
.
A) TOTAL Resistance = 41+18+120 = 179 ohms
<span>Current = V/R = 9 / 179 = 0.0503 A = 50.3 mA </span>
<span>B) V = I*R = .0503 * 41 = 2.06 V </span>
<span>C) V = I*R = .0503 * 18 = 0.91 V </span>
<span>D) V = I*R = .0503 * 120 = 6.03 V</span>
Answer:
40
Explanation:
If it is a flat mirror, the reflection and incidence are the same -- 40 degrees.
If it is anything else, more information is needed.