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Vanyuwa [196]
3 years ago
11

When something is moving, it is in motion. Pressing the gas pedal in a car will put the car in motion. Two important properties

of motion are speed and direction. Speed is how fast an object is moving. If Tony and Tanya both run at the same speed and in the same direction, and they both run for the same amount of time, what can you say about the distance they travel? A) They will run an equal distance. B) Tony will run a greater distance. C) Tanya will run a greater distance. D) Without knowing the exact speed, you can't say for sure.
Physics
2 answers:
Lera25 [3.4K]3 years ago
7 0
<span>If Tony and Tanya both run at the same speed and in the same direction,
and they both run for the same amount of time, there are a lot of things
you can say about them. 

The thing you can say about the distance they travel is "They will both
run the same distance.".  (A)</span>
Alex3 years ago
5 0
A They will run an equal distance
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Answer:

The frequency shift detected is \Delta  f  =1010.3 Hz

Explanation:

From the question we are told that

    The normal frequency of the state highway patrol radar guns f = 8.66 GHz =   8.66 *10^{9} \ Hz

     The speed of approach is v  =  35 .0 \ m/s

       

Now the frequency measure by the the state highway patrol radar guns as your car approaches is mathematically represented as

        f_n  =  f (1 + \frac{v}{c} )

Where c is the speed of light which a has constant value of

     c =  3.0 *10^{8 } \ m/s

  Now

       f_n - f  =  \frac{fv}{c} )

=>    \Delta  f  =   \frac{fv}{c}

substituting values

        \Delta  f  = \frac{ 8.66 *10^{9} *  35}{3.0 *10^8 }

        \Delta  f  =1010.3 Hz

 

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Why is the reflection of a wave at a free boundary different from reflection at a fixed boundary??
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An astronaut is standing on the surface of a planetary satellite that has a radius of 1.74 × 10^6 m and a mass of 7.35 × 10^22 k
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Answer:

2.87 km/s

Explanation:

radius of planet, R = 1.74 x 10^6 m

Mass of planet, M = 7.35 x 10^22 kg

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g=\frac{GM}{R^{2}}

g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.74^{2}\times 10^{12}}

g = 1.62 m/s^2

initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0

Use third equation of motion

v^{2}=u^{2}-2gh

0 = v² - 2 x 1.62 x 2.55 x 10^6

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v = 2874.37 m/s

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