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Vanyuwa [196]
3 years ago
11

When something is moving, it is in motion. Pressing the gas pedal in a car will put the car in motion. Two important properties

of motion are speed and direction. Speed is how fast an object is moving. If Tony and Tanya both run at the same speed and in the same direction, and they both run for the same amount of time, what can you say about the distance they travel? A) They will run an equal distance. B) Tony will run a greater distance. C) Tanya will run a greater distance. D) Without knowing the exact speed, you can't say for sure.
Physics
2 answers:
Lera25 [3.4K]3 years ago
7 0
<span>If Tony and Tanya both run at the same speed and in the same direction,
and they both run for the same amount of time, there are a lot of things
you can say about them. 

The thing you can say about the distance they travel is "They will both
run the same distance.".  (A)</span>
Alex3 years ago
5 0
A They will run an equal distance
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Is it possible to stand backwards on a flight of stairs?
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yes

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3 years ago
Let's examine over the next few questions an NFL kick as described in the 3rd Law video. The announcer claimed that the ball is
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8451.62109367671 Newtons

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1\ kg=1\times 9.8066500286389=9.8066500286389\ N

1 \lb=2.2046226218488\ kg

It is known that

1\ lbs=\dfrac{9.8066500286389}{2.2046226218488}=4.4482216282508\ N

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1900\ lbs=1900\times 4.4482216282508\\\Rightarrow 1900\ lbs=8451.6210936765\ N

The force in Newtons is 8451.6210936765 Newtons

4 0
4 years ago
Juan is on a morning jog. His speed is represented in the graph. At what rate of speed is Juan running between 4min and 6min? Ac
Nesterboy [21]

Answer:

<em>a) The speed of Juan is 250 m/min </em>

<em>b) In that interval, he's at rest </em>

<em>c) Juan would have needed 12 minutes to run 3000 m</em>

Explanation:

<u>Distance vs Time Graph Analysis </u>

If time is on the horizontal axis, and the distance is in the vertical axis, then the slope of the graph represents the instantaneous speed of the moving object. The graph shows three different zones which reflect Juan's jogging at that morning.

a) The period between 4 and 6 minutes clearly shows Juan is moving in such a way the distance increases when time passes. The speed of the motion can be obtained by computing the slope of the line. We can locate the points (4,1000) and (6,1500). We compute the speed  

\displaystyle v=\frac{1500-1000}{6-4}=\frac{500}{2}=250 m/min

The speed of Juan is 250 m/min

b) We can see between 7 and 11 minutes, Juan's distance is not changing because he stopped running. In that interval, he's at rest

c) We have already determined the speed on the first 7 minutes (the same as between 4 and 6 minutes). We know that

\displaystyle v=\frac{x}{t}

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We need to know the time needed to travel x=3000 m at the initial speed v=250 m/min, so we solve the equation for t

\displaystyle t=\frac{x}{v}

\displaystyle t=\frac{3000}{250}=12\ minutes

Juan would have needed 12 minutes to run 3000 m

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4 years ago
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34kurt
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3 years ago
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