Answer:
α =18.75 rad/s²
Explanation:
Given that
Acceleration a = 0.15 g
We know that g =10 m/s²
a= 0.15 x 10 = 1.5 m/s²
d= 16 cm
Radius r= 8 cm
Lets take angular acceleration =α rad/s²
As we know that
a= α r
Now by putting the values
1.5 = α x 0.08
α =18.75 rad/s²
The answer on Edge would be (A.)= Larger and Cooler ! I'm doing the same thing as y'all. Good luck everyone.
The number of cycles of a periodic wave per unit time is called the wave's "frequency". The height at which the peaks of the waves reside is the "amplitude".
The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.
so airspeed due west is = net speed - speed of plane = 240-220= 20 km/h.
airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.
the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h
the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.
if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.
so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.
the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.
To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.
Mathematically this expression can be given as
Where
A = Surface area of the Object
Stefan-Boltzmann constant
e = Emissivity
T = Temperature (Kelvin)
Our values are given as
Replacing at our equation and solving to find the temperature 1 we have,
Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C
