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LUCKY_DIMON [66]

3 years ago

5

Maya and Kenzie are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spil

ls?
A) Using physical and chemical clean up methods to remove the oil
B) Adding more shipping routes
C) Allowing the oil to naturally disperse
D) Increasing overall energy usage

2 answers:

madam [21]3 years ago

6 0

The correct answer is A.

Fittoniya [83]3 years ago

6 0

Maya and Kenzie are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spills?

Answer:

A) Using physical and chemical clean up methods to remove the oil

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An automobile engine has an efficiency of 22.0% and produces 2510 J of work. How much heat is rejected by the engine

katrin [286]

Answer:

If efficiency is .22 then W = .22 * Q where Q is the heat input

Heat Input Q = 2510 / .22 = 11,400 J

Heat rejected = 11.400 - 2510 = 8900 J of heat wasted

Also, 8900 J / (4.19 J / cal) = 2120 cal

5 0

3 years ago

Which of the following items involve a wedge?

elena55 [62]

Answer:

D

Explanation:

Maybe your question is meant to be: which is not a wedge, because wedge is a combination of two inclined planes, use to separate bodies which are held together by large forces. Option A,B & C are all wedge except D.

8 0

3 years ago

Read 2 more answers

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit

Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

$d_1=4.7\times 10^{10} m$

$v_i=9.5\times 10^4 m/s$

$d_2=6\times 10^{12} m$

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

$K_i+U_i=K_f+U_f$

$\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}$

$\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f$

$v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})$

$v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}$

Using the formula

$v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}$

$v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}$

Where mass of sun= $M=1.98\times 10^{30} kg$

$G=6.7\times 10^{-11}$

$v_f=58515.9 m/s$

4 0

3 years ago

(a) Consider a fusion generator built to create 3.00 GW of power. Determine the rate of fuel burning in grams per hour if the DT

Stels [109]

The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × $10^1^3$ J/g per hour

<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>

D + T → He + n
The D-T fusion reaction results in a Helium (He) and neutron (n)

E = 17.59 MeV

Mass = 2.014u + 3.016u

= 5.030u

Energy per Kg = (17.59× $10^6$ ×1.6× $10^-^1^9$ ) ÷ ( 5.030×1.66× $10^-^2^7$ )

= 3.37× $10^1^4$ J/Kg

= 3.0× $10^9$ J/g

Rate of fuel burning in grams per hour = 3.0× $10^9$ × 3600

= 3.6×3.0× $10^1^2$

= 1.08 × $10^1^3$ J/g per hour

To learn more about fusion reactor and energy production, refer

brainly.com/question/13399644

#SPJ4

4 0

2 years ago

Materials that offer little opposition to electron motion are called _________________.

Nuetrik [128]

I believe it is a conductor I am learning this myself so I may be wrong

8 0

3 years ago

Read 2 more answers