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9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.
<h3>What is an ideal gas equation?</h3>The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given data:
Oxygen produced - 1.618 gram
Decomposition of takes place.
Find - Amount of produced.
The decomposition reaction is as follows -
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Moles of gas =
=0.1 moles.
1 mole of is produced from 2 moles of dinitrogen pentoxide
0.1 mole of will be produced from = 0.2 moles.
Now, 2 moles of dinitrogen pentoxide produce 4 moles of
produced will be - 0.4 moles.
Weight of produced - 0.4 X 46
Weight of produced - 18.4 gram
Thus, grams of produced are 18.4
Now calculate the volume of
Given data are:
P=103.25 kPa =1.01899827 atm
T= 22.75 °C +273 = 295.75 K
n=0.4 moles
V=?
R= 0.0821 liter·atm/mol·K
Putting the value in PV=nRT
V =
V =
V= 9.5314 L
Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.
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