Hello!
Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)
- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)
Both of these act in opposite directions. Let's use the equation for torque:

Doing the summation using their respective lever arms:


Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

Now, let's solve for 'T'.

Plugging in the values:

Answer:
0.85 A
Explanation:
the effective current is 0.85 A
Answer:
1 km
Explanation:
Bob travels at one km/h and it takes him one hour to get there.
Answer:
.1 A1 = a1 A1 is amount at .1 %
.01 A2 = a2 A2 is the amount at .01%
a1 + a2 = 454 total of a1 and a2
A = 454 / .03 = 15133.33 tot amount needed
454 = .1 A1 + .01 A2
A2 = 15133.33 - A1
454 = .1 A1 + .01 (15133.33 - A1)
454 = .09 A1 + 151.33
A1 = 302.67 / .09 = 3363
A2 = 15133.3 - 3363 = 11770.3
Check:
.1 * A1 = 336.3
.01 * A2 = 117.7
total = 336.3 + 117.7 = 454