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4vir4ik [10]
3 years ago
14

if 2.0 g of hydrogen sulfide, H2S(g) reacts with 5.0 g of sodium hydroxide what mass of the excess reactant is present when the

reaction is complete
Chemistry
1 answer:
Ronch [10]3 years ago
7 0

Answer: iits 9.g

Explanation:

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What is the name of the molecule shown? Will give brainliest if its right.
nadezda [96]

D. Pentane. Pentane has 5 Carbon and 12 Hydrogen, like the molecule shown.

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3 years ago
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A pure gold ring weighs 23.5 grams. How many atoms of gold<br> are in the ring?
Digiron [165]

The number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

<h3>HOW TO CALCULATE NUMBER OF ATOMS?</h3>

The number of atoms in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

The number of moles in the gold (Au) can be calculated by dividing the mass of gold by its molar mass (196.97g/mol).

no. of moles = 23.5g ÷ 196.97g/mol

no. of moles = 0.119mol

Number of atoms in Au = 0.119 × 6.02 × 10²³

no. of atoms = 7.18 × 10²² atoms.

Therefore, the number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

Learn more about number of atoms at: brainly.com/question/15959704

3 0
3 years ago
What is the<br> mass of 1.82<br> moles of<br> Lithium<br> carbonate?
frutty [35]

Answer:

244.76

Explanation:

The weight of grams by 1.82 moles of lithium carbonate would be: 134.481438 So we need to use this equation to find mass by grams m × g = ms Where m is for moles, g for grams, and ms for mass. So now we need use this equation: 1.82 × 134.481438 = ? 1.82 × 134.481438 = 244.75621716 244.75621716, rounded-up (to the nearest-tenths place) is 244.76. So now you have it! The mass of 1.82 moles of lithium carbonate is 244.76!  

7 0
3 years ago
Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
miskamm [114]

Answer:

544.522 Hours

Explanation:

a) Mass = 12.5 kg = 12500 g

Now, Number of moles is given as

No of moles = Mass of Cr / Molar mass of Cr

=\frac{12500}{52}

= 240.38 moles

Cr^{3+}\Rightarrow 3 mols of electrons are required

\Rightarrow 240.38\times3 =721.14\text{mol of e-}

Converting moles of e- to coulombs of charge, (1 mol of electrons = 96500 C )

Q =721.14 mol×96500 C/mol

=69590010 of charge

We know that, Q = I×t

where Q is charge, I is current and t is time required.

\Rightarrow t =\frac{Q}{I}

=\frac{69590010}{35.5}

=196281.97 seconds

=\frac{1.96281\times10^5}{3600}

=544.522 Hours

3 0
3 years ago
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