D) physical and chemical changes
As we know that rate law expression is
![r = k { |a| }^{2} { |b| }^{2}](https://tex.z-dn.net/?f=r%20%3D%20k%20%7B%20%7Ca%7C%20%7D%5E%7B2%7D%20%20%7B%20%7Cb%7C%20%7D%5E%7B2%7D%20)
(a)
![r = k { |o2| }^{1} { |no2| }^{2}](https://tex.z-dn.net/?f=r%20%3D%20k%20%7B%20%7Co2%7C%20%7D%5E%7B1%7D%20%20%7B%20%7Cno2%7C%20%7D%5E%7B2%7D%20)
(b)
![r = k { |cl2| }^{1}](https://tex.z-dn.net/?f=r%20%3D%20k%20%7B%20%7Ccl2%7C%20%7D%5E%7B1%7D%20)
(c)
![r = k { |chcl3|}^{1} { |cl2| }^{1}](https://tex.z-dn.net/?f=r%20%3D%20k%20%7B%20%7Cchcl3%7C%7D%5E%7B1%7D%20%20%7B%20%7Ccl2%7C%20%7D%5E%7B1%7D%20)
#$# HOPE YOU UNDERSTAND #$#
#$¥ THANK YOU ¥$#
❤ ☺ ☺ ☺ ☺ ☺ ☺ ❤
Answer:
B. products are found on the write side of the arrow in a chemical reaction.
The formula used for determining gas pressure, volume and temperature interaction would be PV=nRT.
<span>• What is the temperature in Kelvins?
</span>You already right at this part. Kelvin temperature formula from celsius should be:
K= C+273.15=
<span>K= 27 +273.15 = 300.15
It is important to remember that the formula in this question is using Kelvin unit at temperature, not Celcius or Fahrenheit.
</span>
<span>• Assuming that everything else remains constant, what will happen to the pressure if the temperature decreases to -15 ºC?
</span>In this case, the temperature is decreased from 27C into -15C and you asked the change in the pressure.
Using PV=nRT formula, you can derive that the temperature will be directly related to pressure. If the temperature decreased, the pressure will be decreased too.
<span> If you increase the number of moles to 6 moles, increase temperature to 400K and reduce the volume to 25 L, what will the new pressure be?
</span>PV=nRT
P= nRT/V
P= 6 moles* <span>0.0821 L*atm/(mol*K) * 400K/25L= 7.8816 atm</span>
Answer:
A = 2A + 3B → 5C
Explanation:
The two molecule of A and three molecules of B will react to form the five molecules of C.
2A + 3B → 5C
Other options are incorrect because,
B = A₂ + B₃ → C₅
in this reaction one molecule of A₂ and one molecule of B₃ combine to form one molecule of C₅.
C = 2A + 5B → 3C
in this reaction two molecules of A and five molecules of B combine to form three molecule of C.
D = A₂ + B₃ → C₃
in this reaction one molecule of A₂ and one molecule of B₃ combine to from one molecule of C₃.