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bazaltina [42]
2 years ago
6

Pendulum clocks are made to run at the correct rate by adjusting the pendulum’s length. Suppose you move from one city to anothe

r where the acceleration due to gravity is slightly greater, taking your pendulum clock with you, will you have to lengthen or shorten the pendulum to keep the correct time, other factors remaining constant? Explain your answer.
Physics
1 answer:
levacccp [35]2 years ago
4 0

Answer:

Obviously Lengthen...   T = 2\pi \sqrt{L/g}   or   g = 4\pi ^{2} L/g

Explanation:

As we can observe from the equation, time period of a simple pendulum depends upon the length directly. When the gravitational acceleration increases the time period of the pendulum decreases and vice versa. So, by increasing the length, the time period can be adjusted...

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
ziro4ka [17]

Answer:

25 m/s

Explanation:

from the question you van see that some detail is missing, however i found this same question using internet search engines on: 'https://www.chegg.com/homework-help/questions-and-answers/light-rail-passenger-trains-provide-transportation-within-cities-speed-slow-nearly-constan-q5808369'

here is the complete question:

'Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 7.0m/s . Once free of this area, it speeds up to 12m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. What is the final Speed?'

SOLUTION

initial speed (u) = 7 m/s

final speed (v) = 13 m/s

initial acceleration time (t1) = 8 s

final acceleration time (t2) = 16 s

what is the higher cruising speed?

acceleration = \frac{final speed (v) - initial speed(u)}{time (t1)}

acceleration = \frac{13-7}{8} = 0.75 m/s^{2}

since the train accelerates at the same rate, the increase in  speed will be = acceleration x time (t2)

= 0.75 x 16 = 12 m/s

therefore the higher cruising speed = increase in speed + initial speed

= 12 + 13 = 25 m/s

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Answer:

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Explanation:

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