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3 years ago

Is it acceptable to mix used absorbents.

2 answers:

7 0

In order to comply with the used oil rule,a facility must properly manage its oil-contaminated sorbents (I.e. , don’t mix other wastes with these sorbets) and it must either recycle sorbets or send them for disposal at a permitted facility that burn them for energy recovery.

Rasek [7]3 years ago

7 0

Answer:

false

Explanation:

it is not acceptable to mix used absorbents

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An AC power generator produces 50 A (rms) at 3600 V. The voltage is stepped up to 100 000 V by an ideal transformer and the ener

RSB [31]

Given:

$I_{rms} = 50 A$

voltage, V = 3600V

step-up voltage, V' = 100000 V

Resistance of line, $R = 100\ohm$

Solution:

To calculate % heat loss in long distance power line:

Power produced by AC generator, P = $50\times 3600$ W

P = 180000 W = 180 kW

At step-up voltage, V = 100000V or 100 kV

current, I = $\frac{P}{V'}$

I = $\frac{1800000}{100000}$

I = 1.8 A

Power line voltage drop is given by:

$V_{drop} = I\times R$

$V_{drop} = 1.8\times 100$

$V_{drop} = 180 V$

Power dissipated in long transmission line $P_{dissipated} = V_{drop}\times I$

Power dissipated in long transmission line $P_{dissipated} = 180\times 1.8$ = 324 W

% Heat loss in power line, $P_{loss} = \frac{P_{dissipated}}{P}\times 100$

% Heat loss in power line, $P_{loss} = \frac{324}{180000}\times 100$

$P_{loss} = 0.18%$

5 0

3 years ago

A soil has the following Green-Ampt parameters Effective porosity 0.400 Initial volumetric moisture content-15% Hydraulic Conduc

Rudik [331]

Answer:

The graphs are attached below

Explanation:

Ans) We know,

F(t) = K(t - to) + zΔ∅ ln[(1 + F(t)/zΔ∅]

where K = hydraulic conductivity =0.1 cm/hr

z = capillary suction =20cm

Δ∅ = ∅ (1 - Se)

∅ = effective porosity , Se = initial moisture content

Δ∅ = 0.40(1 - 0.15)

Δ∅ = 0.34

Now, F(t) = 0.1(t - to) + 20(0.34) ln[ 1 + F(t)/6.8]

F(t) = 0.1(t - to) + 6.8 ln [1+ 0.147 F(t)]

Also, infiltration rate (f),

f = K [(zΔ∅ + F)/F]

f = 0.40 [6.8 + F]/F

Condition of ponding,

Ponding time tp = K zΔ∅ i(i-k)

where, i = rainfall rate (1cm/hr)

tp = 0.40(6.8) / 0.60

tp= 4.53 hours

Now, cumulative infiltraton at ponding Fp = i tp

Fp = 1 x 4.53 or 4.53 cm

For infiltration at time less then ponding time , infiltration rate = rainfall rate

For t = 0.25 hr , f = 1cm/hr ; F = 0.25 x 1 = 0.25 cm

For t = 0.50 hr , f = 1cm/hr ; F = 0.50 cm

For t = 0.75 hr , f = 1cm/hr ; F = 0.75 cm

For t = 1 hr , f = 1cm/hr ; F = 1cm/hr

For t > tp ,

Equivalent time origin(to),

to = tp - 1/K [ Fp - z Δ∅ ln (1+ Fp/zΔ∅)

to = 4.53 - 1/0.40[ 4.53 - 6.8 ln(1 + 0.66)

to = 4.53 - 2.5 ( 4.53 - 3.44)

to = 1.82 hr

Hence,

F = 0.10( t - 1.82) + 6.8 ln[ 1+ 0.147F(t)]

Solving above equation for t by assuming F, and further solving equation for infiltration rate

Ans (a) Following is required curve :

O.S 1-5 2 time Chr)ホー Lt 2 time Chr)

Ans (c) Following is required table :

Ans (d) For time step t = 0.25 hrs

At t < tp ; i = f = 1 cm/hr

F = i x t

F = 1 x 0.25

F = 0.25 cm

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4 years ago

What is the critical path and time duration?

kvasek [131]

The critical path is A-B-C, with a duration of 15 minutes.

<u>Explanation</u>:

The critical path is A-B-C, with a term of 15 minutes. You don't need to be knowledgeable in computer lingo to make sense of this one (as I made sense of it absent a lot of data on that half of the condition). Here's the manner by which I made sense of this.

The main thing I saw was that "predecessor" was utilized, which implies something precedes the other thing. That provided me the primary insight that A precedes B and C, and that B must precede C. Then, I just included the term times for the three ways, which allowed me 15 minutes.

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3 years ago

How much paint would you need to cover one bedroom wall using 2 coats of paint?

Thepotemich [5.8K]

Answer:

One gallon of paint can cover about 400 square feet of wall.

18 x 15 feet is 270 feet of space.

270/400 = .675 gallons for one coat on one wall

.675 x 4 = 2.7 gallons for one coat on all walls

2.7 gallons x 2 = 5.4 gallons of paint in all

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3 years ago

Consider a venture with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.

dangina [55]

Answer:

1913meter per second square.

Explanation:

From the Context the vacuum can be said be the presence of 5e difference below the outside ambient temperature.

For the Venturi.

Please go through the attached file for the rest of the solutions and the answer.

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3 years ago