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viktelen [127]
4 years ago
8

A program contains the following function definition: int cube(int number) { return number * number * number; } Write a stateme

nt that calls this function, passing the value 4 as an argument, and assigns the function's return value to the variable result.
Engineering
1 answer:
Nonamiya [84]4 years ago
8 0

Answer:

The statement can be written as

int result = cube(4);

Explanation:

A function is a block of reusable codes to perform some tasks. For example, the function in the question is to calculate the cube of a number.

A function can also operate on one or more input value (argument) and return a result. The <em>cube </em>function in the question accept one input value through its parameter <em>number </em>and the <em>number</em> will be multiplied by itself twice and return the result.  

To call a function, just simply write the function name followed with parenthesis (e.g. <em>cube()</em>). Within the parenthesis, we can include zero or one or more than one values as argument(s) (e.g. <em>cube(4)</em>).

We can then use the "=" operator to assign the return output of the function to a variable (e.g. <em>int result = cube(4)</em>)

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Mila [183]
<h3 /><h3>\huge \bf༆ Answer ༄</h3>

What is a function ?

An expression or rule that defines a relationship between two variables [ one independent and other dependent variable ]

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y = x² is a function, where y is a dependent variable and x is independent variable.

This function is used to find squares and numbers ~

5 0
3 years ago
Read 2 more answers
Consider a sinusoidal oscillator consisting of an amplifier having a frequency-independent gain A (where A is positive) and a se
mafiozo [28]

Sinusoidal oscillator frequency of oscillation is given below.

Explanation:

The criterion for a stable oscillator is given in the equation

l A(jw)β(jw) l ≥ 1

In this task A represents the gain of the amplifier , and

β represents gain/attenuation of the second-order bandpass filter.

This sinusoidal oscillation is a special edge case where the product is equal to one.

So the condition is A-K=1

to obtain the sustained oscillations at the desired frequency of oscillations, the product of the voltage gain A and the feedback gain β must be one or greater than one. In this case, the amplifier gain A must be 3. Hence, to satisfy the product condition, feedback gain β must be 1/3.

4 0
3 years ago
What Are 2 Properties electromagnets have that permanent magnets do not?
NikAS [45]

Answer:The distinction between a permanent magnet and an electromagnet is essentially one in how the field is created, not the properties of the field afterwards. So electromagnets still have two poles, still attract ferromagnetic materials, and still have poles that repel other like poles and attract unlike poles.

Explanation:

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3 years ago
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Which option identifies what Maria must pay attention to while creating her sketches in the following scenario?
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5 0
3 years ago
A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is
Sauron [17]

The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

  • a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>
  • b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the  isotropic antenna, G = 15 times

The gain in dBi is given as follows;

\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}

Which gives;

\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }

\displaystyle \dfrac{G(dBi)}{10}  = \frac{ln(15)}{ln(10)}

\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

\displaystyle G  = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

  • \displaystyle The \ power \ received \ by \ the \ isotropic \ antenna  = \frac{1 \, mW}{1.64}  \approx \underline {0.61 \, mW}

Learn more here:

brainly.com/question/17587029

4 0
3 years ago
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