Answer: 642.93 g of NaCl
Explanation:
11.00 mol NaCl x __58.448 g__ = 642.928 g of NaCl
1 mol NaCl
I would round to 642.93 g of NaCl, but round to however many significant figures asked for.
My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.
Answer:
Express these numbers in atomic mass units ("u"). Note the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen. ( I asked my teacher about this too)
Explanation:
Answer:
0.077 M
Explanation:
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in Liter = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Molarity:
Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
Answer:
82 N
Step-by-step explanation:
F = ma
Data:
m = 68 kg
a = 1.2 m/s²
Calculation:
F = 68 × 1.2
= 82 N
Answer:
26.4 960 for the first one
8.9569 for the second one
