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My name is Ann [436]
3 years ago
14

The group of test subject that are NOT given the experimental treatment is called what?

Physics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

The group that remains unaltered is called the control group.

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Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven
yKpoI14uk [10]
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
<span>Similarities- These planets all have moons and they both revolve around the sun (obviously).


Hope this helps.</span>
6 0
3 years ago
2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S
artcher [175]
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds


7 0
2 years ago
The difference in outcome between the potential energy in a marshmallow burned over a campfire on the end of a stick and in one
Lapatulllka [165]

Answer:

How fast and efficient the energy is released.

Explanation:

Before burning the marshmallow energy is stored in it in the form of chemical bond energy or chemical potential energy. So upon burning this energy is released. So there will be a difference in energy release from a burned marshmallow and the one we eat straight from package.

5 0
3 years ago
Examine figure 26-1 which area is the convection zone<br><br>A. A<br>B. B<br>C. C<br>D. D
kykrilka [37]
I think the answer is B
4 0
3 years ago
Read 2 more answers
A 6 cm object is 15 cm from a convex lens that has a focal length of 5 cm. What is the distance of the image from the lens, to t
Vesna [10]

Answer:

7.50 cm

Explanation:

The formula

1/v + 1/u = 1/f

Is used.

where.

u is the object distance.

v is the image distance.

f is the focal length of the lens.

1/v + 1/15 = 1/5

1/v = 1/5 - 1/15

1/v = (3-1)/15

1/v = 2/15

2v = 15

V = 15/2

V = 7.5 cm

For focal length, f in lens is always taken as negative for concave and positive for convex. ... And for image distance, V in lens it is taken as positive in Convex lens since image is formed on +X side. It is taken as negative in Concave lens since image is formed in -X side of the Cartesian.

4 0
2 years ago
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