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garik1379 [7]
3 years ago
13

The upward and downward movement of air in the atmosphere creates pressure systems. Arrange the steps in the correct order to de

scribe how a high-pressure system forms and leads to pleasant weather. The skies clear, making way for pleasant weather. Cool, dense air begins to sink downward. Pressure differences cause wind to blow outward. A high-pressure system forms.
Physics
2 answers:
notka56 [123]3 years ago
6 0

Answer:

Cool, dense air begins to sink downward.

A high-pressure system forms.

Pressure differences cause wind to blow outward.

The skies clear, making way for pleasant weather.

Explanation:

OleMash [197]3 years ago
4 0

Answer:

  1. Cool, dense air begins to sink downward.
  2. A high-pressure system forms.
  3. Pressure differences cause wind to blow outward.
  4. The skies clear, making way for pleasant weather.

Explanation:

The air near the land warms up and rises. Cool dense air sinks being heavier. This creates a pressure difference. A high pressure system forms. This difference leads to blowing of wind from High pressure to low pressure area. Eventually sky gets clear and we experience pleasant weather. Hence, the correct order to describe this is:

  1. Cool, dense air begins to sink downward.
  2. A high-pressure system forms.
  3. Pressure differences cause wind to blow outward.
  4. The skies clear, making way for pleasant weather.
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4 years ago
If a display has a dynamic range of 20 dB and the smallest voltage it can handle is 200 mV, then the largest voltage it can hand
DedPeter [7]

Answer:

The largest voltage is 0.02 V.

(d) is correct option.

Explanation:

Given that,

Range = 20 dB

Smallest voltage = 200 mV

We need to calculate the largest voltage

Using formula of voltage gain

G_{dB}=10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})

20 =10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})

2=log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})

10^2=\dfrac{V_{out}^2}{V_{in}^{2}}

\dfrac{V_{out}}{V_{in}^}=10

V_{in}=\dfrac{V_{out}}{10}

V_{in}=\dfrac{200}{10}

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8 0
3 years ago
A block of mass 5 kg is placed on a rough table having a coefficient of static friction μs = 0.2.What is the force required to m
just olya [345]

Answer:

<em>We need to (at least) apply a force of 9.8 N to move the block</em>

Explanation:

<u>Second Newton's Law</u>

If a net force F_n different from zero is applied to an object of mass m, then it will move at an acceleration a, given by

F_n=ma

If we apply a force F to an object placed on a rough surface, the only way to make it move is to beat the friction force  which is given by

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The friction force is

F_r=0.2 (49)=9.8\ N

Thus, we need to (at least) apply a force of 9.8 N to move the block

5 0
4 years ago
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stepladder [879]
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