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Andrew [12]
3 years ago
12

To do a research, a researcher needs to be clear about what he/she is doing, why he/she is doing it and the associated implicati

ons of what he/she is about to do. A. True B. False
Engineering
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

True

Explanation:

To carry out a research in order to that it should yield the desirable result, a researcher must be very clear about his objective for the research.

The researcher must be very much clear about all the  do's and don'ts and all the where, why, what sort of thing, i.e., the researcher must be clear about his/her intentions of carrying out the research, and what research is being carried out by him/her.

The one doing the research must be clear about the implications of the research.

Unless all these things are not clear at the researcher's end the research will not give the desired results.

You might be interested in
Consider a vortex filament of strength in the shape of a closed circular loop of radius R. Obtain an expression for the velocity
zysi [14]

Answer:

<em>v</em><em> </em>= T/(2R)

Explanation:

Given

R = radius

T = strength

From Biot - Savart Law

d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³

Velocity induced at center

<em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>r</em>)/r³

⇒   <em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>R</em>)/R³  (<em>k</em>)        <em>k</em><em>:</em> unit vector perpendicular to plane of loop

⇒   <em>v </em>= (T/4π)(1/R²) ∫ dl

If l ∈  (0, 2πR)

⇒   <em>v </em>= (T/4π)(1/R²)(2πR)  (<em>k</em>)    ⇒   <em>v </em>= T/(2R)  (<em>k</em>)  

3 0
3 years ago
while performing a running compression test how should running compression compare to static compression
algol [13]

Answer:

The idle speed of a running compression should be between 50-75 PSI and that is about half of the static compression.

Explanation:

The Running or Dynamic compression is used to determine how well the cylinder in an engine  is absorbing air, reserving it for the proper length of time, and releasing it to the exhaust. The static or cranking compression test is used to check the sealing of the cylinder. Before performing the running compression test, the static compression test is first performed to rule out other issues like bent valves.

The standard value for the static compression is given by;

Compression ratio * 14.7 = Manufacturers Specification

The running compression should always be half of the static compression.

5 0
2 years ago
____ grinders are used to grind diameters, shoulders, and faces much like the lathe is used for turning, facing, and boring oper
skelet666 [1.2K]

Answer:

Cylindrical

Explanation:

<em>A cylindrical grinder </em><em>is a tool for shaping the exterior of an item. Although cylindrical grinders may produce a wide range of forms, the item must have a central axis of rotation. Shapes such as cylinders, ellipses, cams, and crankshafts are examples of this.</em><em> Cylindrical grinding</em><em> machines are specialized grinding machines that are used to process cylinders, rods, and similar workpieces. The cylinders revolve in one direction between two centers, while the grinding wheel or wheels are close together and rotate in the other direction.</em>

8 0
2 years ago
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Strike441 [17]

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / 0.02^{0.22

K = 815.8165 Mpa

next, we determine the true strain

(εT) = (σT/ K)^1/n

given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

(εT) = 0.04481 mm

Now, we calculate the instantaneous length

l_i = l_0e^{ET

given that l_0 = 480 mm

we substitute

l_i =480mm × e^{0.04481

l_i =  501.998 mm

Now we find the elongation;

Elongation = l_i - l_0

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

6 0
2 years ago
A 12-ft circular steel rod with a diameter of 1.5-in is in tension due to a pulling force of 70-lb. Calculate the stress in the
padilas [110]

Answer:

The stress in the rod is 39.11 psi.

Explanation:

The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:

A=\pi*D^2/4

Replacing the diameter the area results:

A= 17.76 in^2

Therefore the the stress results:

σ = 70/17.76 lb/in^2 = 39.11 lb/in^2= 39.11 psi

5 0
3 years ago
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