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Sunny_sXe [5.5K]
4 years ago
10

What is kirchoff's current law?​

Engineering
2 answers:
Digiron [165]4 years ago
5 0

Answer:

answer is 0

Explanation:

hope it helps

sry but I just kinda needed the points :)

Anastaziya [24]4 years ago
4 0

Answer:

The sum of all currents entering a junction is 0

Explanation:

Current cannot disappear, so the currents leaving a junction have to equal the currents entering a junction. If you would give the currents leaving the junction an opposite sign (e.g., negative) it implies that the sum of all these currents is exactly 0.

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While rowing across a lake, John does 3960 ft-lbs of work over 120 ft. How much force is John using?
Ivanshal [37]

66W. Explanation: Formula of Power: Worktimetaken. Given: Work = 3960J and time taken = 60.0s. Using the formula: Worktimetaken. = 3960J60.0s. = 66W.

6 0
3 years ago
Show how to connect the two circuit building blocks from the previous problem to create a circuit that transforms a priority-enc
Pavel [41]

Answer:

When xo =0, Do= 0, not 1

Explanation:

Use 8×3 priority encoder and 3×8 decoder

8 0
3 years ago
An apple, potato, and onion all taste the same if you eat them with your nose plugged
PolarNik [594]

Answer:

I didn't understand your question or is it a fun fact

3 0
3 years ago
Read 2 more answers
In a mechanical assembly operation, the first work unit required 7.83 min to complete and the learning rate for mechanical assem
Marianna [84]

Answer:

(a) 6.5774 minutes

(b) 4.3879 minutes

(c) 2.459 minutes

(d) 245.902 minutes

Explanation:

The learning curve model follows the following equation:

Y=aX^b

where Y are the units time to produce X units, and a is the time for assembly the first unit. Additionally, b is calculated as:

b=\frac{ln(r)}{ln(2)}

Where r is the learning rate for mechanical assembly. So, b is equal to:

b=\frac{ln(0.84)}{ln(2)}=-0.2515

Then, the equation is:

Y=7.83X^{-0.2515}

Finally, the unit times to produce the second unit are:

Y=7.83(2)^{-0.2515}=6.5774

The 10th unit:

Y=7.83(10)^{-0.2515}=4.3879

The 100th unit:

Y=7.83(100)^{-0.2515}=2.459

Then, the total cumulative time T to produce 100 units in the Crawford model is calculated as:

T=7.83\frac{(100.5)^{1-0.2515}-(0.5)^{1-0.2515})}{1-0.2515} \\T=323.5383

7 0
3 years ago
Is an ideal way for a high school student to see what an engineer does on a typical day but does not provide a hands-on experien
lys-0071 [83]

Answer:

Look at some engineering colleges and set up or join a public zoom meeting. For example, some colleges have sign ups for zoom calls on set dates and you‘re able to ask questions.

Explanation:

8 0
3 years ago
Read 2 more answers
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