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Sunny_sXe [5.5K]

3 years ago

10

What is kirchoff's current law?

2 answers:

Digiron [165]3 years ago

5 0

Answer:

answer is 0

Explanation:

hope it helps

sry but I just kinda needed the points :)

Anastaziya [24]3 years ago

4 0

Answer:

The sum of all currents entering a junction is 0

Explanation:

Current cannot disappear, so the currents leaving a junction have to equal the currents entering a junction. If you would give the currents leaving the junction an opposite sign (e.g., negative) it implies that the sum of all these currents is exactly 0.

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The depletion in the Ozone layer is caused by:

andrew11 [14]

D. Chlorofluorocarbon

This is a man-made carbon that causes the gradual thinning(deception) in the earth’s Ozone layer.

Hope this helped and pls mark as brainliest!

~ Luna

3 0

2 years ago

Read 2 more answers

6) A deep underground cavern Contains 980 cuft

Elza [17]

Answer:

15625 moles of methane is present in this gas deposit

Explanation:

As we know,

PV = nRT

P = Pressure = 230 psia = 1585.79 kPA

V = Volume = 980 cuft = 27750.5 Liters

n = number of moles

R = ideal gas constant = 8.315

T = Temperature = 150°F = 338.706 Kelvin

Substituting the given values, we get -

1585.79 kPA * 27750.5 Liters = n * 8.315 * 338.706 Kelvin

n = (1585.79*27750.5)/(8.315 * 338.706) = 15625

3 0

2 years ago

The diagram illustrates a method of producing plastics called

hodyreva [135]

Answer:

polymerisation,

Explanation:

6 0

1 year ago

Does jupiter have a permanent storm thats looks like a large red spot?

alekssr [168]

Yes it does have a large spot

8 0

2 years ago

A certain part of the cast iron piping of a water distribution system involves a parallel section. Both parallel pipes have a di

Bezzdna [24]

Answer :

<h3>Flow rate in pipe B is = 0.3094 $\frac{m^{3} }{s}$ </h3>

Explanation:

Given :

Length of pipe A $L_{A} = 1500$ m

Length of pipe B $L_{B} = 2500$ m

Flow rate through pipe A $Q_{A} = 0.4 \frac{m^{3} }{s}$

Diameter of pipe $D = 30 \times 10^{-2}$ m

Velocity from pipe A,

$V _{A} = \frac{Q_{A} }{A}$

$V _{A} = \frac{0.4 \times 4 }{\pi ( 30 \times 10^{-2} )^{2} }$

$V_{A} = 5.66$ $\frac{m}{s}$

Here, head loss is same because height is same.

$h_{a} = h_{b}$

$L_{A} V_{A} ^{2} = L_{B} V_{B} ^{2}$

$V_{B} = \sqrt{\frac{1500}{2500}} (5.66)$

$V_{B} = 4.38$ $\frac{m}{s}$

Now rate of flow from pipe B is,

$Q_{B} = V_{B} A$

$Q_{B} = \frac{\pi }{4} (0.3)^{2} \times 4.38$

$Q_{B} = 0.3094$ $\frac{m^{3} }{s}$

4 0

2 years ago