The percent yield of this reaction is calculated as follows
Mg3N2 + 3H2O =2NH3 + 3Mgo
calculate the theoretical yield,
moles=mass/molar mass
moles Mg3N2= 3.82 g/100g/mol= 0.0382 moles(limiting regent)
moles of H2o= 7.73g/18g/mol = 0.429 moles ( in excess_)
by use of mole ratio between Mg3N2 to MgO which is 1:3 the moles of MgO = 0.0382 x3 = 0.1146 moles
mass =moles x molar mass
the theoretical mass is therefore = 0.1146mole x 40 g/mol = 4.58 grams
The % yield = actual mass/theoretical mass x1000
= 3.60/4.584 x100= 78.5%
Answer:
Option D: it's ability to lose electrons
Explanation:
Alkali metals are usually discovered in nature. They have highly reactivity at STP conditions (standard temperature and pressure conditions) and easily lose their outermost electron to form positive ions known that have a charge of +1.
Thus, what can determine the extent of reactivity of an alkali metal, is it's ability to lose electrons
By changing the number of protons in an element, you are fundamentally changing it to a different element.
It’s worth remembering that:
Protons identify the element
Electrons determine properties and behavior of the element
Neutrons contribute to isotopes and just help keep everything stable, by separating the charges. Remember opposites attract. Like charges repel.
Answer:
Gas, has no shape but does take up volume
Water is formed when this happens
