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3 years ago

What are simple machines?

Physics

2 answers:

marta [7]3 years ago

8 0

A lever, pulley, and wheel and axel are all examples of simple machines

Lubov Fominskaja [6]3 years ago

7 0

Simple machines are any basic mechanical device that applies force such as, lever, wedge, inclined plane, wheel and axle, etc.

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The planet Neptune is the farthest planet from the Sun. A satellite is orbiting around Neptune at a distance of 180 km. As the s

stich3 [128]

2,992² + r² = ( r + 180 )²
8,952,064 + r² = r² + 360 r + 32,400
360 r = 8,952,064 - 32,400
360 r = 8,919,664
r = 8,919,664 : 360
r = 24,776.844 km
d = 24,776.844 · 2 = 49,553688 ≈ 49,554 km
Answer:
The approximate diameter of the planet Neptune is 49,554 km.

4 0

4 years ago

A 0.25 kg mass is placed on a vertically oriented spring that is stretched 0.56 meters from its equilibrium position. If the spr

Vitek1552 [10]

Answer:

The speed of the ball when it reaches equilibrium position is 3.31 m/s

Explanation:

Given;

mass of the object, m = 0.25 kg

initial displacement of the object, h₁ = 0.56 m

spring constant, k = 105 N/m

displacement at equilibrium position, h₂ = 0

initial velocity of the object, v₁ = 0

velocity of the object at equilibrium position = v₂

The change in gravitational potential energy at the equilibrium position is given as;

ΔP.E = mg(h₂ - h₁)

The change in kinetic energy of the object at the equilibrium position is given as;

ΔK.E = ¹/₂m(v₂² - v₁²)

Apply the principle of conservation of mechanical energy;

ΔK.E + ΔP.E = 0

¹/₂m(v₂² - v₁²) + mg(h₂ - h₁) = 0

¹/₂m(v₂² - 0) + mg(0 - h₁) = 0

¹/₂mv₂² - mgh₁ = 0

¹/₂mv₂² = mgh

¹/₂v₂² = gh

v₂² = 2gh

v₂ = √2gh

v₂ = √(2 x 9.8 x 0.56)

v₂ = 3.31 m/s

Therefore, the speed of the ball when it reaches equilibrium position is 3.31 m/s

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3 years ago

What is the critical angle for light traveling from crown glass (n = 1.52) into water (n = 1.33)?

Flauer [41]

Answer:

61 degrees, I just did the test.

Explanation:

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3 years ago

Read 2 more answers

The emission of light from a radioisotope occurs during ? decay.

jeka94

Answer:

Gamma

Explanation:

7 0

3 years ago

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The impulse experienced by a body is equivalent to the body’s change in

nika2105 [10]

<h2>Answer: </h2>

Momentum

<h2>Explanation: </h2>

The momentum of a particle is defined as the product of the particle mass and the particle velocity as follows:

$\overrightarrow{p}=m\overrightarrow{v}$

On the other hand, the impulse of a constant force is defined as:

$\overrightarrow{J}=\varSigma\overrightarrow{F}(t_{2}-t_{1})=\varSigma\overrightarrow{F}\Delta t$

We also know that the net force acting on a particle equals the rate of change of the particle’s momentum, so:

$\varSigma\overrightarrow{F}=m\overrightarrow{a}=m\frac{d}{dt}(\overrightarrow{v})=\frac{d}{dt}(m\overrightarrow{v})=\frac{d\overrightarrow{p}}{dt}$

If the force is constant, then $\frac{d\overrightarrow{p}}{dt}$ equals the total change in momentum over a period of time:

$\varSigma\overrightarrow{F}=\frac{\overrightarrow{p_{2}}-\overrightarrow{p_{1}}}{t_{2}-t_{1}} \\ \\ \varSigma\overrightarrow{F}(t_{2}-t_{1})=\overrightarrow{p_{2}}-\overrightarrow{p_{1}} \\ \\ \boxed{\overrightarrow{J}=\Delta \overrightarrow{p}}$

3 0

3 years ago