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solong [7]
3 years ago
7

What term is applied to the situation in which energy has been transferred from faster particles to slower ones and as a result

the particles end up traveling at the same speed?
Physics
2 answers:
Alborosie3 years ago
7 0

Answer:

Conduction

Explanation:

Conduction refers to the transfer of energy through the movement of particles that are in contact with each other. It could be heat conduction, electrical conduction or sound conduction. Heat conduction (or thermal conduction) is the transfer of energy from a warmer substance to a colder one through direct contact, for example, someone touching the handle of a hot metal skillet.

Electrical conduction is the transfer of electrically charged particles through a medium, for example, electricity traveling through the power lines in a house.

Sound conduction (or acoustic conduction) is the transfer of sound waves through a medium, for example, vibrations from loud music passing through a wall.

Nata [24]3 years ago
7 0

Answer:

Conduction

Explanation:

Conduction is applied to the situation in which energy has been transferred from faster particles to slower ones and as a result the particles end up traveling at the same speed. The collision between particles is elastic, hence no energy is lost in the process of collision and hence slower particles are accelerated and faster particles are slowed down to match the speeds while achieving the same temperature.

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Explain why it is important to keep all variables that might affect the dependent variable, other than the manipulated variable
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The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge
lesya [120]

Answer:

Loss, \Delta E=-10.63\ J

Explanation:

Given that,

Mass of particle 1, m_1=m =0.66\ kg

Mass of particle 2, m_2=7.4m =4.884\ kg

Speed of particle 1, v_1=2v_o=2\times 6=12\ m/s

Speed of particle 2, v_2=v_o=6\ m/s

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

m_1v_1+m_2v_2=(m_1+m_2)V

V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}

V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}

V = 6.71 m/s

Initial kinetic energy before the collision,

K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)

K_i=135.43\ J

Final kinetic energy after the collision,

K_f=\dfrac{1}{2}(m_1+m_2)V^2

K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2

K_f=124.80\ J

Lost in kinetic energy,

\Delta K=K_f-K_i

\Delta K=124.80-135.43

\Delta E=-10.63\ J

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

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Explanation:

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