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dmitriy555 [2]
3 years ago
14

Concept Simulation 2.3 provides some background for this problem. A ball is thrown vertically upward, which is the positive dire

ction. A little later it returns to its point of release. The ball is in the air for a total time of 7.96 s. What is its initial velocity? Neglect air resistance.
Physics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer:

39 m/s

Explanation:

Hi!

The equation of motion of the ball is:

y(t) = y_0 + v_{0y}t-(1/2)(9.8 m/s^2)t^2

Where y_0 is the initial horizontal position, which we will take as zero.

v_0y is the initial velocity and t is the time

To find the initial velocity we will set y(7.96s) = 0

0 = v_{0y} (7.96 s)-(4.9 m/s^2)(7.96 s)^2\\v_{0y} =(4.9 m/s^2) (7.96 s)\\v_{0y}=39.004 m/s

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<h2>Answer: B. Gravitational potential energy </h2>

Explanation:

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In the case of the <u>Earth</u>, in which  <u>the gravitational field is considered constant</u>, the value of the gravitational potential energy U_{p} will be:

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3 years ago
The weight of a hydraulic barber's chair with a client is 2100 N. When the barber steps on the input piston with a force of 44 N
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Answer:

\frac{r_1}{r_2}=6.9

Explanation:

According to Pascal's Law, the pressure transmitted from input pedal to the output plunger must be same:

P_1 = P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}\\\\\frac{F_1}{F_2}=\frac{A_1}{A_2}\\\\\frac{F_1}{F_2}=\frac{\pi r_1^2}{\pi r_2^2}\\\\\frac{F_1}{F_2}=\frac{r_1^2}{r_2^2}

where,

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F₂ = Force applied on input piston = 44 N

r₁ = radius of output plunger

r₂ = radius of input piston

Therefore,

\frac{r_1^2}{r_2^2}=\frac{2100\ N}{44\ N}\\\\\frac{r_1}{r_2}=\sqrt{\frac{2100\ N}{44\ N}} \\\\\frac{r_1}{r_2}=6.9

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Reasoning:

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Thus the net force is acting in the north-east direction.

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